Dive into the world of knowledge and get your queries resolved at IDNLearn.com. Get accurate and comprehensive answers to your questions from our community of knowledgeable professionals.

The given mathematical expression appears to be nonsensical as written. It seems to be a combination of incomplete or incorrect LaTeX formatting and disorganized terms. Here is a possible corrected version assuming some intended algebraic expression:

[tex]\[ \hat{s} \cdot \left( -\frac{3}{7} x + \frac{18}{3s} \right) = 1 - 6 \cdot x \][/tex]

If the original question is intended to solve for [tex]\( x \)[/tex], then you can add a prompt for clarity:

Solve for [tex]\( x \)[/tex]:

[tex]\[ \hat{s} \cdot \left( -\frac{3}{7} x + \frac{18}{3s} \right) = 1 - 6 \cdot x \][/tex]

Please ensure that [tex]\( \hat{s} \)[/tex] and other symbols are used correctly as per the context of your problem. If there is specific meaning to these symbols (like a unit vector or a variable), they should be clearly defined in the context.


Sagot :

Sure, let's solve the given equation step-by-step.

The given equation is:

[tex]\[ \left(-\frac{3}{7} x + \frac{18}{3s}\right) = 1 - 6x \][/tex]

First, let's isolate the variable [tex]\( x \)[/tex].

Step 1: Expand and combine like terms.
- To remove fractions, it's sometimes helpful to multiply through by the least common denominator. In this case, we'll work step-by-step through simple operations to maintain clarity.
- Multiply the terms involving [tex]\( x \)[/tex]:
[tex]\[ -\frac{3}{7} x + \frac{18}{3s} = 1 - 6x \][/tex]

Step 2: Get all terms involving [tex]\( x \)[/tex] on one side of the equation and constants on the other.

Add [tex]\( 6x \)[/tex] to both sides:
[tex]\[ -\frac{3}{7} x + 6x + \frac{18}{3s} = 1 \][/tex]

Step 3: Combine terms involving [tex]\( x \)[/tex]:
[tex]\[ \left(-\frac{3}{7} + 6\right)x + \frac{18}{3s} = 1 \][/tex]

Simplify the coefficients of [tex]\( x \)[/tex]:
[tex]\[ \left(6 - \frac{3}{7}\right)x + \frac{18}{3s} = 1 \][/tex]

Convert [tex]\(6\)[/tex] to a fraction with a denominator of [tex]\(7\)[/tex]:
[tex]\[ \left(\frac{42}{7} - \frac{3}{7}\right)x + \frac{18}{3s} = 1 \][/tex]

Combine the fractions:
[tex]\[ \frac{39}{7}x + \frac{18}{3s} = 1 \][/tex]

Step 4: Isolate [tex]\( x \)[/tex]:
Subtract [tex]\(\frac{18}{3s}\)[/tex] from both sides:
[tex]\[ \frac{39}{7}x = 1 - \frac{18}{3s} \][/tex]

Step 5: Solve for [tex]\( x \)[/tex]:
Multiply both sides by [tex]\(\frac{7}{39}\)[/tex]:
[tex]\[ x = \frac{7}{39} \left(1 - \frac{18}{3s}\right) \][/tex]

Simplify the right side:
[tex]\[ x = \frac{7}{39} \left(\frac{3s - 18}{3s}\right) \][/tex]

Step 6: Distribute [tex]\(\frac{7}{39}\)[/tex] across the fraction:
Simplify the fraction inside:
[tex]\[ x = \frac{7}{39} \cdot \frac{3(s - 6)}{3s} \][/tex]

This simplifies to:
[tex]\[ x = \frac{7}{39} \cdot \frac{s - 6}{s} \][/tex]

Combine the constants:
[tex]\[ x = \frac{7}{39} \cdot \frac{s - 6}{s} = \frac{7(s - 6)}{39s} \][/tex]

Finally, simplify further:
[tex]\[ x = \frac{7}{39s} (s - 6) \][/tex]

Combining the fractions gives us:
[tex]\[ x = \frac{7(s - 6)}{39s} = \frac{1}{5.57} \cdot \frac{s - 6}{s} \][/tex]

So, [tex]\( x \)[/tex] can be computed as:
[tex]\[ x = 0.179487179487179 \cdot \frac{s - 6}{s} \][/tex]

Therefore, the solution to the equation is:

[tex]\[ x = 0.179487179487179 \cdot \frac{s - 6}{s} \][/tex]

This provides a detailed step-by-step solution to the given equation.