Connect with knowledgeable experts and enthusiasts on IDNLearn.com. Our platform is designed to provide reliable and thorough answers to all your questions, no matter the topic.
Sagot :
To determine the mass of helium involved when it is heated from [tex]\(20^{\circ} C\)[/tex] to [tex]\(100^{\circ} C\)[/tex] with 520 MJ of energy, we can use the formula that relates energy, mass, specific heat capacity, and temperature change. The formula is:
[tex]\[ Q = m \cdot c \cdot \Delta T \][/tex]
where:
- [tex]\( Q \)[/tex] is the energy transferred (in joules),
- [tex]\( m \)[/tex] is the mass of helium (in kilograms),
- [tex]\( c \)[/tex] is the specific heat capacity (in joules per kilogram per degree Celsius),
- [tex]\( \Delta T \)[/tex] is the change in temperature (in degrees Celsius).
Let's break down the steps to solve for the mass [tex]\( m \)[/tex]:
1. Convert the energy transferred from megajoules to joules:
Since 1 MJ (megajoule) is equal to [tex]\( 10^6 \)[/tex] joules, you need to convert 520 MJ to joules:
[tex]\[ Q = 520 \times 10^6 \, \text{J} \][/tex]
2. Calculate the change in temperature ([tex]\( \Delta T \)[/tex]):
The initial temperature ([tex]\( T_i \)[/tex]) is [tex]\(20^{\circ} C\)[/tex] and the final temperature ([tex]\( T_f \)[/tex]) is [tex]\(100^{\circ} C\)[/tex]:
[tex]\[ \Delta T = T_f - T_i \][/tex]
[tex]\[ \Delta T = 100^{\circ} C - 20^{\circ} C \][/tex]
[tex]\[ \Delta T = 80^{\circ} C \][/tex]
3. Rearrange the energy formula to solve for mass ([tex]\( m \)[/tex]):
[tex]\[ m = \frac{Q}{c \cdot \Delta T} \][/tex]
4. Substitute the given values into the rearranged formula:
Given that [tex]\( Q = 520 \times 10^6 \)[/tex] J, [tex]\( c = 5200 \,\text{J/kg} \cdot ^\circ C \)[/tex], and [tex]\( \Delta T = 80^{\circ} C\)[/tex]:
[tex]\[ m = \frac{520 \times 10^6 \, \text{J}}{5200 \, \text{J/kg} \cdot ^\circ C \times 80^{\circ} C} \][/tex]
5. Perform the calculation:
[tex]\[ m = \frac{520 \times 10^6}{5200 \times 80} \][/tex]
[tex]\[ m = \frac{520 \times 10^6}{416000} \][/tex]
[tex]\[ m = 1250 \, \text{kg} \][/tex]
Therefore, the mass of helium involved is [tex]\( 1250 \)[/tex] kg.
[tex]\[ Q = m \cdot c \cdot \Delta T \][/tex]
where:
- [tex]\( Q \)[/tex] is the energy transferred (in joules),
- [tex]\( m \)[/tex] is the mass of helium (in kilograms),
- [tex]\( c \)[/tex] is the specific heat capacity (in joules per kilogram per degree Celsius),
- [tex]\( \Delta T \)[/tex] is the change in temperature (in degrees Celsius).
Let's break down the steps to solve for the mass [tex]\( m \)[/tex]:
1. Convert the energy transferred from megajoules to joules:
Since 1 MJ (megajoule) is equal to [tex]\( 10^6 \)[/tex] joules, you need to convert 520 MJ to joules:
[tex]\[ Q = 520 \times 10^6 \, \text{J} \][/tex]
2. Calculate the change in temperature ([tex]\( \Delta T \)[/tex]):
The initial temperature ([tex]\( T_i \)[/tex]) is [tex]\(20^{\circ} C\)[/tex] and the final temperature ([tex]\( T_f \)[/tex]) is [tex]\(100^{\circ} C\)[/tex]:
[tex]\[ \Delta T = T_f - T_i \][/tex]
[tex]\[ \Delta T = 100^{\circ} C - 20^{\circ} C \][/tex]
[tex]\[ \Delta T = 80^{\circ} C \][/tex]
3. Rearrange the energy formula to solve for mass ([tex]\( m \)[/tex]):
[tex]\[ m = \frac{Q}{c \cdot \Delta T} \][/tex]
4. Substitute the given values into the rearranged formula:
Given that [tex]\( Q = 520 \times 10^6 \)[/tex] J, [tex]\( c = 5200 \,\text{J/kg} \cdot ^\circ C \)[/tex], and [tex]\( \Delta T = 80^{\circ} C\)[/tex]:
[tex]\[ m = \frac{520 \times 10^6 \, \text{J}}{5200 \, \text{J/kg} \cdot ^\circ C \times 80^{\circ} C} \][/tex]
5. Perform the calculation:
[tex]\[ m = \frac{520 \times 10^6}{5200 \times 80} \][/tex]
[tex]\[ m = \frac{520 \times 10^6}{416000} \][/tex]
[tex]\[ m = 1250 \, \text{kg} \][/tex]
Therefore, the mass of helium involved is [tex]\( 1250 \)[/tex] kg.
Thank you for joining our conversation. Don't hesitate to return anytime to find answers to your questions. Let's continue sharing knowledge and experiences! IDNLearn.com has the solutions you’re looking for. Thanks for visiting, and see you next time for more reliable information.