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Right Triangles and Trigonometry

Select the correct answer.

The shortest side of a right triangle measures [tex]$3 \sqrt{3}$[/tex] inches. One angle of the triangle measures [tex]$60^{\circ}$[/tex]. What is the length, in inches, of the hypotenuse of the triangle?

A. 3
B. [tex][tex]$6 \sqrt{2}$[/tex][/tex]
C. 6
D. [tex]$6 \sqrt{3}$[/tex]


Sagot :

To solve this problem, it's important to note that we're dealing with a 30-60-90 right triangle, which has some special properties. In a 30-60-90 triangle, the relationships between the lengths of the sides are always consistent. These relationships are:

1. The side opposite the 30-degree angle (the shortest side) has a length of [tex]\( x \)[/tex].
2. The side opposite the 60-degree angle (the medium side) is [tex]\( x\sqrt{3} \)[/tex].
3. The hypotenuse (the side opposite the 90-degree angle) is [tex]\( 2x \)[/tex].

In this problem, we are given that the shortest side (opposite the 30-degree angle) measures [tex]\( 3\sqrt{3} \)[/tex] inches. According to the special properties of a 30-60-90 triangle:

[tex]\[ x = 3\sqrt{3} \][/tex]

The hypotenuse in a 30-60-90 triangle is twice the length of the shortest side. Therefore:

[tex]\[ \text{Hypotenuse} = 2x = 2(3\sqrt{3}) \][/tex]

By calculating the above expression, we get:

[tex]\[ \text{Hypotenuse} = 6\sqrt{3} \][/tex]

So, the length of the hypotenuse is [tex]\( 6\sqrt{3} \)[/tex] inches.

Thus, the correct answer is:

D. [tex]\( 6\sqrt{3} \)[/tex]