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Find the [tex]$n$[/tex]th term [tex]$a_n$[/tex] of the geometric sequence described below, where [tex]$r$[/tex] is the common ratio:

[tex]\[
\begin{array}{l}
a_7 = 64, \; r = -2 \\
a_n = \square
\end{array}
\][/tex]


Sagot :

To find the first term [tex]\(a\)[/tex] of the geometric sequence, we will use the information provided and the properties of geometric sequences.

A geometric sequence has the form:
[tex]\[ a_n = a \cdot r^{n-1} \][/tex]

We are given:
[tex]\[ a_7 = 64 \][/tex]
[tex]\[ r = -2 \][/tex]

We need to find the first term [tex]\(a\)[/tex].

Using the formula for the [tex]\(n\)[/tex]th term:
[tex]\[ a_7 = a \cdot r^{7-1} \][/tex]
[tex]\[ a_7 = a \cdot r^6 \][/tex]

Substituting the given values into the formula:
[tex]\[ 64 = a \cdot (-2)^6 \][/tex]

We know that:
[tex]\[ (-2)^6 = 64 \][/tex]

So the equation becomes:
[tex]\[ 64 = a \cdot 64 \][/tex]

To isolate [tex]\(a\)[/tex], we divide both sides of the equation by 64:
[tex]\[ a = \frac{64}{64} \][/tex]
[tex]\[ a = 1.0 \][/tex]

Thus, the first term of the geometric sequence is:
[tex]\[ a = 1.0 \][/tex]
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