The function f is continuous on the closed interval closed interval from pi over 3 to 5 times pi all over 3.. Selected values of f are given in the table: x2 times pi all over 34 times pi all over 35 times pi all over 3 f(x)0.4775−0.2387−0.1194k What value of k in the table would give the equation f(x) = 0 at least two solutions in the interval closed interval from pi over 3 to 5 times pi all over 3? negative pi over 3 −0.0955 0.0955 negative 5 times pi all over 3

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Simonestephenson14idn Simonestephenson14idn

02-08-2024
Mathematics

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The function f is continuous on the closed interval closed interval from pi over 3 to 5 times pi all over 3.. Selected values of f are given in the table: x2 times pi all over 34 times pi all over 35 times pi all over 3 f(x)0.4775−0.2387−0.1194k What value of k in the table would give the equation f(x) = 0 at least two solutions in the interval closed interval from pi over 3 to 5 times pi all over 3? negative pi over 3 −0.0955 0.0955 negative 5 times pi all over 3

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