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What is the center of a circle represented by the equation [tex](x+9)^2+(y-6)^2=10^2[/tex]?

A. [tex](-9, 6)[/tex]
B. [tex](-6, 9)[/tex]
C. [tex](6, -9)[/tex]
D. [tex](9, -6)[/tex]


Sagot :

To determine the center of a circle from its equation, we need to understand the general form of a circle's equation. The standard form of a circle's equation is:

[tex]\[ (x - h)^2 + (y - k)^2 = r^2 \][/tex]

In this equation:
- [tex]\((h, k)\)[/tex] represents the center of the circle.
- [tex]\(r\)[/tex] represents the radius.

Given the equation:

[tex]\[ (x + 9)^2 + (y - 6)^2 = 10^2 \][/tex]

Our goal is to identify the values of [tex]\(h\)[/tex] and [tex]\(k\)[/tex] that represent the center of the circle. To convert the given equation into the standard form, we recognize the following:

1. [tex]\((x + 9)^2\)[/tex] can be rewritten as [tex]\((x - (-9))^2\)[/tex]. This tells us that [tex]\(h = -9\)[/tex].
2. [tex]\((y - 6)^2\)[/tex] already matches the standard form, so [tex]\(k = 6\)[/tex].

Therefore, the center of the circle [tex]\((h, k)\)[/tex] is:

[tex]\[ (-9, 6) \][/tex]

This matches one of the provided answer choices. Thus, the correct answer is:

[tex]\[ (-9, 6) \][/tex]