From beginner to expert, IDNLearn.com has answers for everyone. Join our Q&A platform to get accurate and thorough answers to all your pressing questions.
Sagot :
Sure! Let's break down the question and find step-by-step solutions for everything.
Given:
- [tex]\( P(T) = 0.4 \)[/tex]
- [tex]\( P(\operatorname{S \cap T}) = 0.5 \)[/tex]
- [tex]\( P(S \cup T) \)[/tex]
We need to find:
(a) [tex]\( P(S) \)[/tex]
(b) [tex]\( P\left(S' \cap T\right) \)[/tex]
### (a) Finding [tex]\( P(S) \)[/tex]
First, let's find [tex]\( P(S) \)[/tex].
We know from the given information that [tex]\( P(S \cap T) = 0.5 \)[/tex]. The probability [tex]\( P(S) \)[/tex] can be calculated via the relationship with the intersection probability. According to the problem statement, [tex]\( P(S \cap T) = 0.5 \)[/tex], and we also have:
[tex]\[ P(S \cap T) = P(S | T) \cdot P(T) \][/tex]
Here, [tex]\( P(S | T) \)[/tex] is the conditional probability of [tex]\( S \)[/tex] given [tex]\( T \)[/tex].
Given [tex]\( P(T) = 0.4 \)[/tex], we can rearrange the formula:
[tex]\[ P(S) = \frac{P(S \cap T)}{P(T)} \][/tex]
[tex]\[ P(S) = \frac{0.5}{0.4} \][/tex]
[tex]\[ P(S) = 1.25 \][/tex]
So,
[tex]\[ P(S) = 1.25 \][/tex]
### (b) Finding [tex]\( P\left(S' \cap T\right) \)[/tex]
Next, we need to find [tex]\( P\left(S' \cap T\right) \)[/tex].
Recall that [tex]\( S' \)[/tex] represents the complement of event [tex]\( S \)[/tex]. The probability of [tex]\( S' \cap T \)[/tex] can be calculated using the following relationship:
[tex]\[ P(T) = P(S \cap T) + P(S' \cap T) \][/tex]
From here, we can rearrange to find [tex]\( P(S' \cap T) \)[/tex]:
[tex]\[ P(S' \cap T) = P(T) - P(S \cap T) \][/tex]
Substituting the given values:
[tex]\[ P(S' \cap T) = 0.4 - 0.15 \][/tex]
[tex]\[ P(S' \cap T) = 0.25 \][/tex]
So,
[tex]\[ P\left(S' \cap T\right) = 0.25 \][/tex]
### Summary
(a) The probability of [tex]\( S \)[/tex], [tex]\( P(S) \)[/tex], is [tex]\( 1.25 \)[/tex].
(b) The probability of [tex]\( S' \cap T \)[/tex], [tex]\( P\left(S' \cap T\right) \)[/tex], is [tex]\( 0.25 \)[/tex].
I hope this solution helps clarify how to find the required probabilities step-by-step! If you have any further questions, feel free to ask.
Given:
- [tex]\( P(T) = 0.4 \)[/tex]
- [tex]\( P(\operatorname{S \cap T}) = 0.5 \)[/tex]
- [tex]\( P(S \cup T) \)[/tex]
We need to find:
(a) [tex]\( P(S) \)[/tex]
(b) [tex]\( P\left(S' \cap T\right) \)[/tex]
### (a) Finding [tex]\( P(S) \)[/tex]
First, let's find [tex]\( P(S) \)[/tex].
We know from the given information that [tex]\( P(S \cap T) = 0.5 \)[/tex]. The probability [tex]\( P(S) \)[/tex] can be calculated via the relationship with the intersection probability. According to the problem statement, [tex]\( P(S \cap T) = 0.5 \)[/tex], and we also have:
[tex]\[ P(S \cap T) = P(S | T) \cdot P(T) \][/tex]
Here, [tex]\( P(S | T) \)[/tex] is the conditional probability of [tex]\( S \)[/tex] given [tex]\( T \)[/tex].
Given [tex]\( P(T) = 0.4 \)[/tex], we can rearrange the formula:
[tex]\[ P(S) = \frac{P(S \cap T)}{P(T)} \][/tex]
[tex]\[ P(S) = \frac{0.5}{0.4} \][/tex]
[tex]\[ P(S) = 1.25 \][/tex]
So,
[tex]\[ P(S) = 1.25 \][/tex]
### (b) Finding [tex]\( P\left(S' \cap T\right) \)[/tex]
Next, we need to find [tex]\( P\left(S' \cap T\right) \)[/tex].
Recall that [tex]\( S' \)[/tex] represents the complement of event [tex]\( S \)[/tex]. The probability of [tex]\( S' \cap T \)[/tex] can be calculated using the following relationship:
[tex]\[ P(T) = P(S \cap T) + P(S' \cap T) \][/tex]
From here, we can rearrange to find [tex]\( P(S' \cap T) \)[/tex]:
[tex]\[ P(S' \cap T) = P(T) - P(S \cap T) \][/tex]
Substituting the given values:
[tex]\[ P(S' \cap T) = 0.4 - 0.15 \][/tex]
[tex]\[ P(S' \cap T) = 0.25 \][/tex]
So,
[tex]\[ P\left(S' \cap T\right) = 0.25 \][/tex]
### Summary
(a) The probability of [tex]\( S \)[/tex], [tex]\( P(S) \)[/tex], is [tex]\( 1.25 \)[/tex].
(b) The probability of [tex]\( S' \cap T \)[/tex], [tex]\( P\left(S' \cap T\right) \)[/tex], is [tex]\( 0.25 \)[/tex].
I hope this solution helps clarify how to find the required probabilities step-by-step! If you have any further questions, feel free to ask.
We appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. Your questions are important to us at IDNLearn.com. Thanks for stopping by, and come back for more reliable solutions.