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Sagot :
To solve for [tex]\( u \cdot v \)[/tex], where [tex]\( u = 1 + i \sqrt{3} \)[/tex] and [tex]\( v = 1 - i \sqrt{3} \)[/tex], follow these steps:
1. Express the problem:
We need to find the product of [tex]\( u \)[/tex] and [tex]\( v \)[/tex]:
[tex]\[ u \cdot v = (1 + i \sqrt{3})(1 - i \sqrt{3}) \][/tex]
2. Use the difference of squares formula:
[tex]\[ (a + b)(a - b) = a^2 - b^2 \][/tex]
Here, [tex]\( a = 1 \)[/tex] and [tex]\( b = i\sqrt{3} \)[/tex].
3. Apply the formula to our specific terms:
[tex]\[ (1 + i \sqrt{3})(1 - i \sqrt{3}) = 1^2 - (i \sqrt{3})^2 \][/tex]
4. Compute each term:
- [tex]\( 1^2 = 1 \)[/tex]
- [tex]\((i \sqrt{3})^2 = i^2 \cdot (\sqrt{3})^2 = -1 \cdot 3 = -3 \)[/tex] because [tex]\( i^2 = -1 \)[/tex].
5. Subtract the results:
[tex]\[ 1 - (-3) = 1 + 3 = 4 \][/tex]
Therefore, the product [tex]\( u \cdot v \)[/tex] is [tex]\( 4 \)[/tex]. Thus, the correct answer is:
[tex]\[ \boxed{4} \][/tex]
1. Express the problem:
We need to find the product of [tex]\( u \)[/tex] and [tex]\( v \)[/tex]:
[tex]\[ u \cdot v = (1 + i \sqrt{3})(1 - i \sqrt{3}) \][/tex]
2. Use the difference of squares formula:
[tex]\[ (a + b)(a - b) = a^2 - b^2 \][/tex]
Here, [tex]\( a = 1 \)[/tex] and [tex]\( b = i\sqrt{3} \)[/tex].
3. Apply the formula to our specific terms:
[tex]\[ (1 + i \sqrt{3})(1 - i \sqrt{3}) = 1^2 - (i \sqrt{3})^2 \][/tex]
4. Compute each term:
- [tex]\( 1^2 = 1 \)[/tex]
- [tex]\((i \sqrt{3})^2 = i^2 \cdot (\sqrt{3})^2 = -1 \cdot 3 = -3 \)[/tex] because [tex]\( i^2 = -1 \)[/tex].
5. Subtract the results:
[tex]\[ 1 - (-3) = 1 + 3 = 4 \][/tex]
Therefore, the product [tex]\( u \cdot v \)[/tex] is [tex]\( 4 \)[/tex]. Thus, the correct answer is:
[tex]\[ \boxed{4} \][/tex]
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