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What is the pH of a 0.014 M solution of hydroiodic acid?

Sagot :

To determine the pH of a 0.014 M solution of hydroiodic acid (HI), follow these steps:

1. Understanding Hydroiodic Acid (HI):
Hydroiodic acid is a strong acid, which means it dissociates completely in water. Therefore, the concentration of hydrogen ions [tex]\([\text{H}^+]\)[/tex] in the solution will be equal to the concentration of the acid.

2. Determine the Concentration of Hydrogen Ions [tex]\([\text{H}^+]\)[/tex]:
Since HI dissociates completely:
[tex]\[ \text{HI} \rightarrow \text{H}^+ + \text{I}^- \][/tex]
The concentration of [tex]\(\text{H}^+\)[/tex] ions is the same as the concentration of the HI solution, which is 0.014 M.

3. Calculating the pH:
The pH of a solution is calculated using the formula:
[tex]\[ \text{pH} = -\log[\text{H}^+] \][/tex]
Here, [tex]\([\text{H}^+]\)[/tex] is the concentration of hydrogen ions in moles per liter (M).

4. Substituting the Values:
Substitute [tex]\([\text{H}^+]\)[/tex] = 0.014 into the pH formula:
[tex]\[ \text{pH} = -\log(0.014) \][/tex]

5. Result:
After performing the calculation, the pH of the solution is found to be approximately 1.85.

Therefore, the pH of a 0.014 M solution of hydroiodic acid is 1.85.