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Sagot :
Certainly! Let's solve the equation step-by-step:
The equation we need to solve is:
[tex]\[ 8d \div 4 = 5 - 3d \][/tex]
1. Simplify the left side of the equation:
[tex]\[ 8d \div 4 = 2d \][/tex]
So, the equation simplifies to:
[tex]\[ 2d = 5 - 3d \][/tex]
2. Get all [tex]\(d\)[/tex] terms on one side:
Add [tex]\(3d\)[/tex] to both sides of the equation to eliminate the [tex]\(d\)[/tex] term on the right side:
[tex]\[ 2d + 3d = 5 - 3d + 3d \][/tex]
[tex]\[ 5d = 5 \][/tex]
3. Solve for [tex]\(d\)[/tex]:
To isolate [tex]\(d\)[/tex], divide both sides of the equation by 5:
[tex]\[ d = \frac{5}{5} \][/tex]
[tex]\[ d = 1 \][/tex]
So, we have found that [tex]\(d = 1\)[/tex].
4. Verify the solution:
To ensure the correctness, substitute [tex]\(d = 1\)[/tex] back into the original equation:
- The left side:
[tex]\[ 8d \div 4 = 8 \times 1 \div 4 = 2 \][/tex]
- The right side:
[tex]\[ 5 - 3d = 5 - 3 \times 1 = 5 - 3 = 2 \][/tex]
Both sides equal 2, confirming that our solution is correct.
Thus, the value of [tex]\(d\)[/tex] that satisfies the equation is [tex]\(\boxed{1}\)[/tex].
The equation we need to solve is:
[tex]\[ 8d \div 4 = 5 - 3d \][/tex]
1. Simplify the left side of the equation:
[tex]\[ 8d \div 4 = 2d \][/tex]
So, the equation simplifies to:
[tex]\[ 2d = 5 - 3d \][/tex]
2. Get all [tex]\(d\)[/tex] terms on one side:
Add [tex]\(3d\)[/tex] to both sides of the equation to eliminate the [tex]\(d\)[/tex] term on the right side:
[tex]\[ 2d + 3d = 5 - 3d + 3d \][/tex]
[tex]\[ 5d = 5 \][/tex]
3. Solve for [tex]\(d\)[/tex]:
To isolate [tex]\(d\)[/tex], divide both sides of the equation by 5:
[tex]\[ d = \frac{5}{5} \][/tex]
[tex]\[ d = 1 \][/tex]
So, we have found that [tex]\(d = 1\)[/tex].
4. Verify the solution:
To ensure the correctness, substitute [tex]\(d = 1\)[/tex] back into the original equation:
- The left side:
[tex]\[ 8d \div 4 = 8 \times 1 \div 4 = 2 \][/tex]
- The right side:
[tex]\[ 5 - 3d = 5 - 3 \times 1 = 5 - 3 = 2 \][/tex]
Both sides equal 2, confirming that our solution is correct.
Thus, the value of [tex]\(d\)[/tex] that satisfies the equation is [tex]\(\boxed{1}\)[/tex].
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