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Applicants to a university were surveyed about their planned living arrangements for the coming year. The results of the survey are displayed in the two-way frequency table.

\begin{tabular}{|l|c|c|c|}
\cline{2-4}
\multicolumn{1}{c|}{} & On-Campus & Off-Campus & Total \\
\hline
Transfer Applicants & 38 & 66 & 104 \\
\hline
Freshman Applicants & 85 & 52 & 137 \\
\hline
Total & 123 & 118 & 241 \\
\hline
\end{tabular}

What is the probability that an applicant planning to stay off-campus is a transfer applicant?

A. 0.490
B. 0.559
C. 0.525
D. 0.635


Sagot :

To find the probability that an applicant planning to stay off-campus is a transfer applicant, we follow these steps:

1. Identify the given data:
- Total number of applicants planning to stay off-campus: [tex]\( 118 \)[/tex]
- Number of transfer applicants planning to stay off-campus: [tex]\( 66 \)[/tex]

2. Calculate the probability:
The probability that an applicant planning to stay off-campus is a transfer applicant is calculated as the ratio of the number of transfer applicants planning to stay off-campus to the total number of applicants planning to stay off-campus.

[tex]\[ \text{Probability} = \frac{\text{Number of transfer applicants planning to stay off-campus}}{\text{Total number of applicants planning to stay off-campus}} \][/tex]

3. Substitute the values:
[tex]\[ \text{Probability} = \frac{66}{118} \][/tex]

4. Simplify the fraction or convert it to a decimal:
[tex]\[ \frac{66}{118} \approx 0.559 \][/tex]

Given this result, we can see it matches option B in the list of choices provided.

Therefore, the probability that an applicant planning to stay off-campus is a transfer applicant is [tex]\( 0.559 \)[/tex].

Final Answer: B. 0.559