IDNLearn.com provides a user-friendly platform for finding and sharing knowledge. Our experts are available to provide in-depth and trustworthy answers to any questions you may have.
Sagot :
Let's break down the answers step by step:
1. Calculating [tex]\(P(\text{Boy})\)[/tex]:
- The probability of selecting a boy from the total number of students.
- Total number of boys = 160
- Total number of students = 240
[tex]\[ P(\text{Boy}) = \frac{\text{Number of Boys}}{\text{Total Students}} = \frac{160}{240} = \frac{2}{3} \approx 0.67 \][/tex]
2. Calculating [tex]\(P(\text{Boy} \mid \text{Indoor Recess})\)[/tex]:
- The probability of selecting a boy given that the student prefers indoor recess.
- Number of boys who prefer indoor recess = 64
- Total number of students who prefer indoor recess = 96
[tex]\[ P(\text{Boy} \mid \text{Indoor Recess}) = \frac{\text{Number of Boys who prefer Indoor Recess}}{\text{Total Indoor Recess Students}} = \frac{64}{96} = \frac{2}{3} \approx 0.67 \][/tex]
3. Determining if the events are independent:
- Events are independent if:
[tex]\[ P(\text{Boy and Indoor Recess}) = P(\text{Boy}) \times P(\text{Indoor Recess}) \][/tex]
- Calculate [tex]\(P(\text{Boy and Indoor Recess})\)[/tex]:
- Number of boys who prefer indoor recess = 64
- Total number of students = 240
[tex]\[ P(\text{Boy and Indoor Recess}) = \frac{64}{240} = \frac{4}{15} \][/tex]
- Calculate [tex]\(P(\text{Boy}) \times P(\text{Indoor Recess})\)[/tex]:
- [tex]\(P(\text{Indoor Recess})\)[/tex]:
- Total number of students who prefer indoor recess = 96
- Total number of students = 240
[tex]\[ P(\text{Indoor Recess}) = \frac{96}{240} = \frac{2}{5} \][/tex]
[tex]\[ P(\text{Boy}) \times P(\text{Indoor Recess}) = \left( \frac{2}{3} \right) \times \left( \frac{2}{5} \right) = \frac{4}{15} \][/tex]
- Since:
[tex]\[ P(\text{Boy and Indoor Recess}) = P(\text{Boy}) \times P(\text{Indoor Recess}) = \frac{4}{15} \][/tex]
- The events are independent since the probabilities match.
Therefore, your final answers in the drop-down menu should be:
[tex]\[ \begin{array}{l} P(\text { Boy })= \frac{2}{3} \\ P(\text { Boy } \mid \text { Indoor Recess })= \frac{2}{3} \end{array} \][/tex]
[tex]\[ \text{The events of the student being a boy and the student preferring indoor recess are \textbf{independent}} \][/tex]
1. Calculating [tex]\(P(\text{Boy})\)[/tex]:
- The probability of selecting a boy from the total number of students.
- Total number of boys = 160
- Total number of students = 240
[tex]\[ P(\text{Boy}) = \frac{\text{Number of Boys}}{\text{Total Students}} = \frac{160}{240} = \frac{2}{3} \approx 0.67 \][/tex]
2. Calculating [tex]\(P(\text{Boy} \mid \text{Indoor Recess})\)[/tex]:
- The probability of selecting a boy given that the student prefers indoor recess.
- Number of boys who prefer indoor recess = 64
- Total number of students who prefer indoor recess = 96
[tex]\[ P(\text{Boy} \mid \text{Indoor Recess}) = \frac{\text{Number of Boys who prefer Indoor Recess}}{\text{Total Indoor Recess Students}} = \frac{64}{96} = \frac{2}{3} \approx 0.67 \][/tex]
3. Determining if the events are independent:
- Events are independent if:
[tex]\[ P(\text{Boy and Indoor Recess}) = P(\text{Boy}) \times P(\text{Indoor Recess}) \][/tex]
- Calculate [tex]\(P(\text{Boy and Indoor Recess})\)[/tex]:
- Number of boys who prefer indoor recess = 64
- Total number of students = 240
[tex]\[ P(\text{Boy and Indoor Recess}) = \frac{64}{240} = \frac{4}{15} \][/tex]
- Calculate [tex]\(P(\text{Boy}) \times P(\text{Indoor Recess})\)[/tex]:
- [tex]\(P(\text{Indoor Recess})\)[/tex]:
- Total number of students who prefer indoor recess = 96
- Total number of students = 240
[tex]\[ P(\text{Indoor Recess}) = \frac{96}{240} = \frac{2}{5} \][/tex]
[tex]\[ P(\text{Boy}) \times P(\text{Indoor Recess}) = \left( \frac{2}{3} \right) \times \left( \frac{2}{5} \right) = \frac{4}{15} \][/tex]
- Since:
[tex]\[ P(\text{Boy and Indoor Recess}) = P(\text{Boy}) \times P(\text{Indoor Recess}) = \frac{4}{15} \][/tex]
- The events are independent since the probabilities match.
Therefore, your final answers in the drop-down menu should be:
[tex]\[ \begin{array}{l} P(\text { Boy })= \frac{2}{3} \\ P(\text { Boy } \mid \text { Indoor Recess })= \frac{2}{3} \end{array} \][/tex]
[tex]\[ \text{The events of the student being a boy and the student preferring indoor recess are \textbf{independent}} \][/tex]
Thank you for joining our conversation. Don't hesitate to return anytime to find answers to your questions. Let's continue sharing knowledge and experiences! IDNLearn.com is committed to providing accurate answers. Thanks for stopping by, and see you next time for more solutions.