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Sagot :
To solve [tex]\(16 \times 12\)[/tex] using the distributive property, follow these steps:
1. Break Down the Numbers:
- We can split 12 into a sum of two numbers that are easier to work with.
- Let's break 12 into 10 and 2. So, [tex]\(12 = 10 + 2\)[/tex].
2. Apply the Distributive Property:
- According to the distributive property of multiplication over addition, [tex]\(a \times (b + c) = (a \times b) + (a \times c)\)[/tex].
- In this case, [tex]\(16 \times 12\)[/tex] can be written as:
[tex]\[ 16 \times (10 + 2) \][/tex]
3. Multiply Separately:
- First, multiply 16 by 10:
[tex]\[ 16 \times 10 = 160 \][/tex]
- Next, multiply 16 by 2:
[tex]\[ 16 \times 2 = 32 \][/tex]
4. Add the Intermediate Products:
- Now, add the results of the two multiplications:
[tex]\[ 160 + 32 = 192 \][/tex]
Therefore, [tex]\(16 \times 12 = 192\)[/tex].
1. Break Down the Numbers:
- We can split 12 into a sum of two numbers that are easier to work with.
- Let's break 12 into 10 and 2. So, [tex]\(12 = 10 + 2\)[/tex].
2. Apply the Distributive Property:
- According to the distributive property of multiplication over addition, [tex]\(a \times (b + c) = (a \times b) + (a \times c)\)[/tex].
- In this case, [tex]\(16 \times 12\)[/tex] can be written as:
[tex]\[ 16 \times (10 + 2) \][/tex]
3. Multiply Separately:
- First, multiply 16 by 10:
[tex]\[ 16 \times 10 = 160 \][/tex]
- Next, multiply 16 by 2:
[tex]\[ 16 \times 2 = 32 \][/tex]
4. Add the Intermediate Products:
- Now, add the results of the two multiplications:
[tex]\[ 160 + 32 = 192 \][/tex]
Therefore, [tex]\(16 \times 12 = 192\)[/tex].
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