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Three capacitors with capacitances, [tex]C_1 = 1 \, \text{F}[/tex], [tex]C_2 = 2 \, \text{F}[/tex], and [tex]C_3 = 3 \, \text{F}[/tex], are connected to an 8 V source. What is the effective capacitance when the capacitors are connected in:

(a) series
(b) parallel


Sagot :

Certainly! Let's tackle each part of the problem one by one:

### Part (a): Effective Capacitance When Connected in Series

When capacitors are connected in series, the reciprocal of the total capacitance [tex]\( C_{\text{series}} \)[/tex] is the sum of the reciprocals of the individual capacitances:

[tex]\[ \frac{1}{C_{\text{series}}} = \frac{1}{C_1} + \frac{1}{C_2} + \frac{1}{C_3} \][/tex]

Given the values:
- [tex]\( C_1 = 1 \, \text{F} \)[/tex]
- [tex]\( C_2 = 2 \, \text{F} \)[/tex]
- [tex]\( C_3 = 3 \, \text{F} \)[/tex]

Substitute these values into the formula:

[tex]\[ \frac{1}{C_{\text{series}}} = \frac{1}{1} + \frac{1}{2} + \frac{1}{3} \][/tex]

Calculate the individual fractions:

[tex]\[ \frac{1}{C_{\text{series}}} = 1 + 0.5 + 0.333\overline{3} \][/tex]

Adding these together:

[tex]\[ \frac{1}{C_{\text{series}}} = 1.833\overline{3} \][/tex]

Now find the reciprocal of this sum to get [tex]\( C_{\text{series}} \)[/tex]:

[tex]\[ C_{\text{series}} = \frac{1}{1.833\overline{3}} \approx 0.545 \, \text{F} \][/tex]

So, the effective capacitance when the capacitors are connected in series is approximately:

[tex]\[ C_{\text{series}} \approx 0.545 \, \text{F} \][/tex]

### Part (b): Effective Capacitance When Connected in Parallel

When capacitors are connected in parallel, the total capacitance [tex]\( C_{\text{parallel}} \)[/tex] is the sum of the individual capacitances:

[tex]\[ C_{\text{parallel}} = C_1 + C_2 + C_3 \][/tex]

Again, using the given values:

- [tex]\( C_1 = 1 \, \text{F} \)[/tex]
- [tex]\( C_2 = 2 \, \text{F} \)[/tex]
- [tex]\( C_3 = 3 \, \text{F} \)[/tex]

Substitute these values into the formula:

[tex]\[ C_{\text{parallel}} = 1 + 2 + 3 \][/tex]

Add these together:

[tex]\[ C_{\text{parallel}} = 6 \, \text{F} \][/tex]

So, the effective capacitance when the capacitors are connected in parallel is:

[tex]\[ C_{\text{parallel}} = 6 \, \text{F} \][/tex]

### Summary

(a) The effective capacitance when the capacitors are connected in series is approximately [tex]\( 0.545 \, \text{F} \)[/tex].

(b) The effective capacitance when the capacitors are connected in parallel is [tex]\( 6 \, \text{F} \)[/tex].