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How many ways can two out of 10 children be lined up, followed by lining up four out of 10 men, where order matters, and then include 3 out of 10 women where any combination will work?

A. [tex]$4.12 \times 10^{12}$[/tex]
B. [tex]$4.57 \times 10^{10}$[/tex]
C. [tex]$7,357,000$[/tex]
D. [tex]$54,432,000$[/tex]


Sagot :

To solve this problem, let's break it down step by step.

### Step 1: Selecting and Arranging Children

We need to choose 2 out of 10 children and then arrange them.

1. Selecting 2 out of 10 children:
The number of ways to choose 2 children from 10 is given by the combination formula [tex]\( \binom{10}{2} \)[/tex]:

[tex]\[ \binom{10}{2} = \frac{10!}{2!(10-2)!} = \frac{10 \times 9}{2 \times 1} = 45 \][/tex]

However, in the context of permutations when selecting orders:

[tex]\[ P(10, 2) = \frac{10!}{(10-2)!} = 10 \times 9 = 90 \][/tex]

### Step 2: Selecting and Arranging Men

Next, we need to line up 4 out of 10 men, where the order matters.

2. Selecting 4 out of 10 men:
Similarly, we use the permutation formula [tex]\( P(10, 4) \)[/tex]:

[tex]\[ P(10, 4) = \frac{10!}{(10-4)!} = 10 \times 9 \times 8 \times 7 = 5040 \][/tex]

### Step 3: Selecting Women

For the women, we need to select 3 out of 10, but the order does not matter.

3. Choosing 3 out of 10 women:
The number of ways to choose 3 women from 10 is given by the combination formula [tex]\( \binom{10}{3} \)[/tex]:

[tex]\[ \binom{10}{3} = \frac{10!}{3!(10-3)!} = \frac{10 \times 9 \times 8}{3 \times 2 \times 1} = 120 \][/tex]

### Step 4: Combining All Possible Ways

Finally, we multiply the number of ways to line up 2 out of 10 children, 4 out of 10 men, and choose 3 out of 10 women.

[tex]\[ \text{Total ways} = 90 \times 5040 \times 120 \][/tex]

Calculating the total:

[tex]\[ 90 \times 5040 = 453600 \][/tex]

[tex]\[ 453600 \times 120 = 54432000 \][/tex]

Thus, the total number of ways to accomplish this task is:

[tex]\[ 54,432,000 \][/tex]

### Conclusion

Therefore, the correct answer is:

[tex]\[ \boxed{54,432,000} \][/tex]
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