Get the best answers to your questions with the help of IDNLearn.com's experts. Ask your questions and receive comprehensive, trustworthy responses from our dedicated team of experts.
Sagot :
To determine which set of numbers is arranged in increasing order, let's examine the values of each of the numbers involved:
1. [tex]\(\pi \approx 3.141592653589793\)[/tex]
2. [tex]\(\sqrt{10} \approx 3.162277660168379\)[/tex]
3. [tex]\(3.14\)[/tex] is already given as [tex]\(3.14\)[/tex]
4. [tex]\(\frac{22}{7} \approx 3.142857142857143\)[/tex]
Given these approximations, we need to verify the order of numbers in each set:
### Set A: [tex]\(\pi, \sqrt{10}, 3.14, \frac{22}{7}\)[/tex]
- [tex]\(\pi \approx 3.1416\)[/tex]
- [tex]\(\sqrt{10} \approx 3.1623\)[/tex]
- [tex]\(3.14\)[/tex]
- [tex]\(\frac{22}{7} \approx 3.1429\)[/tex]
The sequence is: [tex]\(3.1416, 3.1623, 3.14, 3.1429\)[/tex]
Clearly, [tex]\(3.14\)[/tex] is out of order here, so Set A is not correct.
### Set B: [tex]\(3.14, \pi, \frac{22}{7}, \sqrt{10}\)[/tex]
- [tex]\(3.14\)[/tex]
- [tex]\(\pi \approx 3.1416\)[/tex]
- [tex]\(\frac{22}{7} \approx 3.1429\)[/tex]
- [tex]\(\sqrt{10} \approx 3.1623\)[/tex]
The sequence is: [tex]\(3.14, 3.1416, 3.1429, 3.1623\)[/tex]
This sequence is in increasing order, so Set B is the correct answer.
### Set C: [tex]\(\frac{22}{7}, \sqrt{10}, 3.14, \pi\)[/tex]
- [tex]\(\frac{22}{7} \approx 3.1429\)[/tex]
- [tex]\(\sqrt{10} \approx 3.1623\)[/tex]
- [tex]\(3.14\)[/tex]
- [tex]\(\pi \approx 3.1416\)[/tex]
The sequence is: [tex]\(3.1429, 3.1623, 3.14, 3.1416\)[/tex]
Clearly, [tex]\(3.14\)[/tex] and [tex]\(\pi\)[/tex] are out of order here, so Set C is not correct.
### Set D: [tex]\(\sqrt{10}, \frac{22}{7}, 3.14, \pi\)[/tex]
- [tex]\(\sqrt{10} \approx 3.1623\)[/tex]
- [tex]\(\frac{22}{7} \approx 3.1429\)[/tex]
- [tex]\(3.14\)[/tex]
- [tex]\(\pi \approx 3.1416\)[/tex]
The sequence is: [tex]\(3.1623, 3.1429, 3.14, 3.1416\)[/tex]
Clearly, this sequence is also not in the increasing order, so Set D is not correct.
Therefore, the set where the numbers are arranged in increasing order is:
[tex]\[ \boxed{B} \][/tex]
1. [tex]\(\pi \approx 3.141592653589793\)[/tex]
2. [tex]\(\sqrt{10} \approx 3.162277660168379\)[/tex]
3. [tex]\(3.14\)[/tex] is already given as [tex]\(3.14\)[/tex]
4. [tex]\(\frac{22}{7} \approx 3.142857142857143\)[/tex]
Given these approximations, we need to verify the order of numbers in each set:
### Set A: [tex]\(\pi, \sqrt{10}, 3.14, \frac{22}{7}\)[/tex]
- [tex]\(\pi \approx 3.1416\)[/tex]
- [tex]\(\sqrt{10} \approx 3.1623\)[/tex]
- [tex]\(3.14\)[/tex]
- [tex]\(\frac{22}{7} \approx 3.1429\)[/tex]
The sequence is: [tex]\(3.1416, 3.1623, 3.14, 3.1429\)[/tex]
Clearly, [tex]\(3.14\)[/tex] is out of order here, so Set A is not correct.
### Set B: [tex]\(3.14, \pi, \frac{22}{7}, \sqrt{10}\)[/tex]
- [tex]\(3.14\)[/tex]
- [tex]\(\pi \approx 3.1416\)[/tex]
- [tex]\(\frac{22}{7} \approx 3.1429\)[/tex]
- [tex]\(\sqrt{10} \approx 3.1623\)[/tex]
The sequence is: [tex]\(3.14, 3.1416, 3.1429, 3.1623\)[/tex]
This sequence is in increasing order, so Set B is the correct answer.
### Set C: [tex]\(\frac{22}{7}, \sqrt{10}, 3.14, \pi\)[/tex]
- [tex]\(\frac{22}{7} \approx 3.1429\)[/tex]
- [tex]\(\sqrt{10} \approx 3.1623\)[/tex]
- [tex]\(3.14\)[/tex]
- [tex]\(\pi \approx 3.1416\)[/tex]
The sequence is: [tex]\(3.1429, 3.1623, 3.14, 3.1416\)[/tex]
Clearly, [tex]\(3.14\)[/tex] and [tex]\(\pi\)[/tex] are out of order here, so Set C is not correct.
### Set D: [tex]\(\sqrt{10}, \frac{22}{7}, 3.14, \pi\)[/tex]
- [tex]\(\sqrt{10} \approx 3.1623\)[/tex]
- [tex]\(\frac{22}{7} \approx 3.1429\)[/tex]
- [tex]\(3.14\)[/tex]
- [tex]\(\pi \approx 3.1416\)[/tex]
The sequence is: [tex]\(3.1623, 3.1429, 3.14, 3.1416\)[/tex]
Clearly, this sequence is also not in the increasing order, so Set D is not correct.
Therefore, the set where the numbers are arranged in increasing order is:
[tex]\[ \boxed{B} \][/tex]
We appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. Your search for answers ends at IDNLearn.com. Thanks for visiting, and we look forward to helping you again soon.