From beginner to expert, IDNLearn.com has answers for everyone. Join our platform to receive prompt and accurate responses from experienced professionals in various fields.
Sagot :
To determine the quotient of the expression
[tex]\[ \left(15n^2 - 27n\right) \div 3n \][/tex]
we can follow these steps:
1. Divide each term in the numerator by the term in the denominator individually:
- The first term in the numerator is [tex]\(15n^2\)[/tex]:
[tex]\[ \frac{15n^2}{3n} \][/tex]
Simplifying this term:
[tex]\[ \frac{15n^2}{3n} = 5n \quad \text{(since } 15 ÷ 3 = 5 \text{ and } n^2 ÷ n = n \text{)} \][/tex]
- The second term in the numerator is [tex]\(-27n\)[/tex]:
[tex]\[ \frac{-27n}{3n} \][/tex]
Simplifying this term:
[tex]\[ \frac{-27n}{3n} = -9 \quad \text{(since } -27 ÷ 3 = -9 \text{ and } n ÷ n = 1 \text{)} \][/tex]
2. Combine these simplified terms:
- The resulting expression becomes:
[tex]\[ 5n - 9 \][/tex]
Therefore, the quotient of the given expression is:
[tex]\[ \boxed{5n - 9} \][/tex]
[tex]\[ \left(15n^2 - 27n\right) \div 3n \][/tex]
we can follow these steps:
1. Divide each term in the numerator by the term in the denominator individually:
- The first term in the numerator is [tex]\(15n^2\)[/tex]:
[tex]\[ \frac{15n^2}{3n} \][/tex]
Simplifying this term:
[tex]\[ \frac{15n^2}{3n} = 5n \quad \text{(since } 15 ÷ 3 = 5 \text{ and } n^2 ÷ n = n \text{)} \][/tex]
- The second term in the numerator is [tex]\(-27n\)[/tex]:
[tex]\[ \frac{-27n}{3n} \][/tex]
Simplifying this term:
[tex]\[ \frac{-27n}{3n} = -9 \quad \text{(since } -27 ÷ 3 = -9 \text{ and } n ÷ n = 1 \text{)} \][/tex]
2. Combine these simplified terms:
- The resulting expression becomes:
[tex]\[ 5n - 9 \][/tex]
Therefore, the quotient of the given expression is:
[tex]\[ \boxed{5n - 9} \][/tex]
We appreciate your contributions to this forum. Don't forget to check back for the latest answers. Keep asking, answering, and sharing useful information. Your questions deserve accurate answers. Thank you for visiting IDNLearn.com, and see you again for more solutions.