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Which is the focus and directrix of the parabola with equation (y 1.5)2 = 4(x – 2)?

Sagot :

Answer:

focus : (3,-1.5)

directrix : x = 1

Step-by-step explanation:

The focus is located  p units horizontally from the vertex. If the parabola opens to the right, the focus is at  (h + p , k ) . If it opens to the left, the focus is at  ( h − p , k ) .

The directrix is a vertical line located p units horizontally from the vertex. If the parabola opens to the right, the directrix is the line x = h − p. If it opens to the left, the directrix is the line x = h + p.

Solving:

[tex]\[(y + 1.5)^2 = 4(x - 2)\][/tex]

[tex]\[h = 2, \quad k = -1.5, \quad 4p = 4 \implies\boxed{ p = 1}\][/tex]

[tex]\[\text{Vertex} = (2, -1.5)\][/tex]

[tex]\(p = 1\) \text{and the parabola expands to the right the focus is: } \\\\\((2 + 1, -1.5) =\boxed{ (3, -1.5)}[/tex]

[tex]\text{The directrix is the vertical line}~ \(x = 2 - 1 = 1\).\\\\\boxed{x = 1}[/tex]