IDNLearn.com: Your reliable source for finding precise answers. Discover comprehensive answers to your questions from our community of knowledgeable experts.
Sagot :
Sure, let's solve for [tex]\( u \)[/tex] step-by-step.
Given the formula:
[tex]\[ E = \frac{m}{2g} \left( v^2 - u^2 \right) \][/tex]
1. Isolate the term involving [tex]\( u \)[/tex]:
[tex]\[ E = \frac{m}{2g} \left( v^2 - u^2 \right) \][/tex]
Multiply both sides by [tex]\( \frac{2g}{m} \)[/tex] to isolate the term with [tex]\( u \)[/tex]:
[tex]\[ \frac{2gE}{m} = v^2 - u^2 \][/tex]
2. Rearrange the equation to make [tex]\( u^2 \)[/tex] the subject:
[tex]\[ u^2 = v^2 - \frac{2gE}{m} \][/tex]
3. Solve for [tex]\( u \)[/tex] by taking the square root of both sides:
[tex]\[ u = \pm \sqrt{v^2 - \frac{2gE}{m}} \][/tex]
So, the solutions for [tex]\( u \)[/tex] are:
[tex]\[ u = \sqrt{v^2 - \frac{2gE}{m}} \quad \text{or} \quad u = -\sqrt{v^2 - \frac{2gE}{m}} \][/tex]
In other words, the two possible values for [tex]\( u \)[/tex] are:
[tex]\[ u = \sqrt{v^2 - \frac{2gE}{m}} \][/tex]
[tex]\[ u = -\sqrt{v^2 - \frac{2gE}{m}} \][/tex]
Given the formula:
[tex]\[ E = \frac{m}{2g} \left( v^2 - u^2 \right) \][/tex]
1. Isolate the term involving [tex]\( u \)[/tex]:
[tex]\[ E = \frac{m}{2g} \left( v^2 - u^2 \right) \][/tex]
Multiply both sides by [tex]\( \frac{2g}{m} \)[/tex] to isolate the term with [tex]\( u \)[/tex]:
[tex]\[ \frac{2gE}{m} = v^2 - u^2 \][/tex]
2. Rearrange the equation to make [tex]\( u^2 \)[/tex] the subject:
[tex]\[ u^2 = v^2 - \frac{2gE}{m} \][/tex]
3. Solve for [tex]\( u \)[/tex] by taking the square root of both sides:
[tex]\[ u = \pm \sqrt{v^2 - \frac{2gE}{m}} \][/tex]
So, the solutions for [tex]\( u \)[/tex] are:
[tex]\[ u = \sqrt{v^2 - \frac{2gE}{m}} \quad \text{or} \quad u = -\sqrt{v^2 - \frac{2gE}{m}} \][/tex]
In other words, the two possible values for [tex]\( u \)[/tex] are:
[tex]\[ u = \sqrt{v^2 - \frac{2gE}{m}} \][/tex]
[tex]\[ u = -\sqrt{v^2 - \frac{2gE}{m}} \][/tex]
We appreciate your contributions to this forum. Don't forget to check back for the latest answers. Keep asking, answering, and sharing useful information. Find precise solutions at IDNLearn.com. Thank you for trusting us with your queries, and we hope to see you again.