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In this spreadsheet, what will be returned from the formula [tex]=A4*D3[/tex]?

\begin{tabular}{|c|c|c|c|c|c|}
\hline
& A & B & C & D & E \\
\hline
1 & 95 & 37 & 1 & 6 & 27 \\
\hline
2 & 5 & 0 & 49 & 31 & 5 \\
\hline
3 & 78 & 2 & 6 & 2 & 3 \\
\hline
4 & 6 & 30 & 10 & 62 & 40 \\
\hline
5 & 42 & 7 & 21 & 9 & 10 \\
\hline
\end{tabular}

A. 8
B. 12
C. 3
D. 4


Sagot :

To determine the value returned by the formula =A4\*D3 using the given spreadsheet data, follow these steps:

1. Identify the value in cell A4.
- From the spreadsheet provided:
[tex]\[ \begin{array}{|c|c|c|c|c|c|c|} \hline (n / a) & A & B & C & D & E \\ \hline 1 & 95 & 37 & 1 & 6 & 27 \\ \hline 2 & 5 & 0 & 49 & 31 & 5 \\ \hline 3 & 78 & 2 & 6 & 2 & 3 \\ \hline 4 & 6 & 30 & 10 & 62 & 40 \\ \hline 5 & 42 & 7 & 21 & 9 & 10 \\ \hline \end{array} \][/tex]
- The value of cell A4 is 6 (found in row 4, column A).

2. Identify the value in cell D3.
- From the spreadsheet provided:
[tex]\[ \begin{array}{|c|c|c|c|c|c|c|} \hline (n / a) & A & B & C & D & E \\ \hline 1 & 95 & 37 & 1 & 6 & 27 \\ \hline 2 & 5 & 0 & 49 & 31 & 5 \\ \hline 3 & 78 & 2 & 6 & 2 & 3 \\ \hline 4 & 6 & 30 & 10 & 62 & 40 \\ \hline 5 & 42 & 7 & 21 & 9 & 10 \\ \hline \end{array} \][/tex]
- The value of cell D3 is 2 (found in row 3, column D).

3. Multiply the values of A4 and D3:
- [tex]\( \text{A4} \times \text{D3} = 6 \times 2 \)[/tex]

4. The result of [tex]\( 6 \times 2 \)[/tex] is:

[tex]\[ 12 \][/tex]

Therefore, the formula =A4\*D3 will return 12.