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Using Ohm's law, what is the amp draw of a circuit with a voltage of [tex]$240 V$[/tex] and a resistance of [tex]$10 \Omega$[/tex]?

Select one:
A. 240 A
B. 34 A
C. 24 A
D. 2.4 A

Sagot :

GinnyAnsweridn
To determine the current (amp draw) in a circuit using Ohm's Law, we need to apply the formula:

[tex]\[ I = \frac{V}{R} \][/tex]

where:
- [tex]\( I \)[/tex] is the current in amperes (A),
- [tex]\( V \)[/tex] is the voltage in volts (V),
- [tex]\( R \)[/tex] is the resistance in ohms ([tex]\(\Omega\)[/tex]).

In this problem, the voltage [tex]\( V \)[/tex] is given as 240 V, and the resistance [tex]\( R \)[/tex] is 10 [tex]\(\Omega\)[/tex]. We can substitute these values into the formula:

[tex]\[ I = \frac{240 \, \text{V}}{10 \, \Omega} \][/tex]

Performing the division:

[tex]\[ I = 24 \, \text{A} \][/tex]

Thus, the current or amp draw of the circuit is 24 A.

Therefore, the correct answer is:
C. 24 A
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