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What is the slope of the line that passes through the points [tex]\((-9, -9)\)[/tex] and [tex]\((-9, -7)\)[/tex]?

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Sagot :

To find the slope of the line that passes through the points [tex]\((-9, -9)\)[/tex] and [tex]\((-9, -7)\)[/tex], we need to use the formula for the slope between two points [tex]\((x_1, y_1)\)[/tex] and [tex]\((x_2, y_2)\)[/tex]:

[tex]\[ m = \frac{y_2 - y_1}{x_2 - x_1} \][/tex]

Given the points [tex]\((-9, -9)\)[/tex] and [tex]\((-9, -7)\)[/tex], we can substitute the values for the coordinates into the formula:

[tex]\[ x_1 = -9, \quad y_1 = -9, \quad x_2 = -9, \quad y_2 = -7 \][/tex]

First, calculate the change in the y-coordinates ([tex]\(\Delta y\)[/tex]):

[tex]\[ \Delta y = y_2 - y_1 = -7 - (-9) = -7 + 9 = 2 \][/tex]

Next, calculate the change in the x-coordinates ([tex]\(\Delta x\)[/tex]):

[tex]\[ \Delta x = x_2 - x_1 = -9 - (-9) = -9 + 9 = 0 \][/tex]

Now, substitute the values of [tex]\(\Delta y\)[/tex] and [tex]\(\Delta x\)[/tex] into the slope formula:

[tex]\[ m = \frac{\Delta y}{\Delta x} = \frac{2}{0} \][/tex]

The denominator is zero, which means the slope is undefined. This happens because the line is vertical; all points on the line have the same x-coordinate.

In conclusion, the slope of the line that passes through the points [tex]\((-9, -9)\)[/tex] and [tex]\((-9, -7)\)[/tex] is undefined.