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Sagot :
To determine the width of the rectangle given the length and the perimeter, let's follow these steps:
1. Understand the problem: You are given:
- The length of the rectangle is 12 inches.
- The perimeter of the rectangle is 56 inches.
2. Recall the formula for the perimeter of a rectangle:
The perimeter [tex]\( P \)[/tex] of a rectangle is given by:
[tex]\[ P = 2 \times ( \text{length} + \text{width} ) \][/tex]
3. Plug in the known values into the formula:
[tex]\[ 56 = 2 \times ( 12 + \text{width} ) \][/tex]
4. Isolate the term involving the width:
Divide both sides of the equation by 2 to isolate the terms inside the parentheses:
[tex]\[ 28 = 12 + \text{width} \][/tex]
5. Solve for the width of the rectangle:
Subtract 12 from both sides of the equation to find the width:
[tex]\[ \text{width} = 28 - 12 = 16 \][/tex]
6. Conclusion:
The width of the rectangle is 16 inches.
Hence, the best answer is:
OB. 16 in.
1. Understand the problem: You are given:
- The length of the rectangle is 12 inches.
- The perimeter of the rectangle is 56 inches.
2. Recall the formula for the perimeter of a rectangle:
The perimeter [tex]\( P \)[/tex] of a rectangle is given by:
[tex]\[ P = 2 \times ( \text{length} + \text{width} ) \][/tex]
3. Plug in the known values into the formula:
[tex]\[ 56 = 2 \times ( 12 + \text{width} ) \][/tex]
4. Isolate the term involving the width:
Divide both sides of the equation by 2 to isolate the terms inside the parentheses:
[tex]\[ 28 = 12 + \text{width} \][/tex]
5. Solve for the width of the rectangle:
Subtract 12 from both sides of the equation to find the width:
[tex]\[ \text{width} = 28 - 12 = 16 \][/tex]
6. Conclusion:
The width of the rectangle is 16 inches.
Hence, the best answer is:
OB. 16 in.
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