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Simplify the expression using the order of operations.

[tex]\[
\begin{aligned}
\left(4+2^3\right) \times 6-10 & =(4+\square) \times 6-10 \\
& =\square \times 6-10 \\
& =\square-10 \\
& =\square
\end{aligned}
\][/tex]

Sagot :

GinnyAnsweridn
Certainly! Let's simplify the given expression step-by-step using the order of operations (PEMDAS/BODMAS: Parentheses, Exponents, Multiplication and Division (from left to right), Addition and Subtraction (from left to right)).

Given expression:
[tex]\[ \left(4 + 2^3\right) \times 6 - 10 \][/tex]

Step 1: Exponentiation

First, we need to evaluate the exponent [tex]\(2^3\)[/tex]:
[tex]\[ 2^3 = 8 \][/tex]

Updating our expression, we get:
[tex]\[ \left(4 + 8\right) \times 6 - 10 \][/tex]

Step 2: Parentheses

Next, we calculate the sum inside the parentheses:
[tex]\[ 4 + 8 = 12 \][/tex]

Updating our expression, we get:
[tex]\[ 12 \times 6 - 10 \][/tex]

Step 3: Multiplication

Now, we perform the multiplication:
[tex]\[ 12 \times 6 = 72 \][/tex]

Updating our expression, we get:
[tex]\[ 72 - 10 \][/tex]

Step 4: Subtraction

Finally, we perform the subtraction:
[tex]\[ 72 - 10 = 62 \][/tex]

So, the simplified expression is:
[tex]\[ 62 \][/tex]
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