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You toss a coin and roll a number cube. The table shows the sample space, where H means heads, T means tails, and the numbers represent the number cube roll.

\begin{tabular}{|c|c|c|c|c|c|c|}
\hline & [tex]$1$[/tex] & [tex]$2$[/tex] & [tex]$3$[/tex] & [tex]$4$[/tex] & [tex]$5$[/tex] & [tex]$6$[/tex] \\
\hline H & H1 & H2 & H3 & H4 & H5 & H6 \\
\hline T & T1 & T2 & T3 & T4 & T5 & T6 \\
\hline
\end{tabular}

What is the probability of tossing heads and rolling a number less than 5?


Sagot :

To determine the probability of tossing heads and rolling a number less than 5, we need to follow these steps:

1. Understand the sample space:
- The sample space includes all possible outcomes when tossing a coin and rolling a number cube.
- For heads (H), the outcomes are H1, H2, H3, H4, H5, and H6.
- For tails (T), the outcomes are T1, T2, T3, T4, T5, and T6.
- Thus, the total number of outcomes is 12, which includes 6 outcomes for heads and 6 for tails.

2. Identify favorable outcomes:
- We want the outcomes where the coin shows heads and the number rolled is less than 5.
- These outcomes are H1, H2, H3, and H4.

3. Count the number of favorable outcomes:
- The number of favorable outcomes (tossing heads and rolling a number less than 5) is 4.

4. Calculate the probability:
- Probability is calculated as the number of favorable outcomes divided by the total number of outcomes.
[tex]\[ \text{Probability} = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} \][/tex]
- Here, the number of favorable outcomes is 4, and the total number of outcomes is 12.
[tex]\[ \text{Probability} = \frac{4}{12} = \frac{1}{3} \][/tex]

So, the probability of tossing heads and rolling a number less than 5 is approximately 0.3333, or [tex]\(\frac{1}{3}\)[/tex] when expressed as a fraction.
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