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Sagot :
To identify the correct parameters [tex]\( p \)[/tex] and [tex]\( n \)[/tex] for this binomial distribution scenario, let's break down the information provided:
1. Probability of Winning (Success): The probability of winning an arcade game is given as 0.718.
2. Number of Trials (Games Played): It is stated that you play the arcade game 20 times. This means the number of trials is 20.
In a binomial distribution scenario:
- [tex]\( p \)[/tex] represents the probability of success in a single trial.
- [tex]\( n \)[/tex] represents the number of independent trials.
Given this information:
- The probability of success, [tex]\( p \)[/tex], is 0.718.
- The number of trials, [tex]\( n \)[/tex], is 20.
Thus, the parameters for this binomial distribution are:
- [tex]\( p = 0.718 \)[/tex]
- [tex]\( n = 20 \)[/tex]
Therefore, the correct answer is:
[tex]\[ p = 0.718, n = 20 \][/tex]
1. Probability of Winning (Success): The probability of winning an arcade game is given as 0.718.
2. Number of Trials (Games Played): It is stated that you play the arcade game 20 times. This means the number of trials is 20.
In a binomial distribution scenario:
- [tex]\( p \)[/tex] represents the probability of success in a single trial.
- [tex]\( n \)[/tex] represents the number of independent trials.
Given this information:
- The probability of success, [tex]\( p \)[/tex], is 0.718.
- The number of trials, [tex]\( n \)[/tex], is 20.
Thus, the parameters for this binomial distribution are:
- [tex]\( p = 0.718 \)[/tex]
- [tex]\( n = 20 \)[/tex]
Therefore, the correct answer is:
[tex]\[ p = 0.718, n = 20 \][/tex]
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