Sure, let's look at the problem step-by-step and solve each part accordingly.
### Problem Statement:
48 parts by weight of a divalent metal combine with 32 parts by weight of oxygen. We need to find:
(a) Equivalent weight of the metal
(b) Atomic weight of the metal
(c) Valency of the metal
### Given Data:
- Weight of metal = 48 parts
- Weight of oxygen = 32 parts
- Valency of the metal = 2 (since it is mentioned the metal is divalent)
### (a) Equivalent Weight of Metal
The equivalent weight of a metal is calculated using the formula:
[tex]\[ \text{Equivalent weight} = \frac{\text{Atomic weight of the metal}}{\text{Valency}} \][/tex]
From the given data, we know the weight of the metal and its valency. Therefore:
[tex]\[ \text{Equivalent weight of the metal} = \frac{\text{Weight of the metal}}{\text{Valency}} \][/tex]
[tex]\[ \text{Equivalent weight of the metal} = \frac{48 \text{ parts}}{2} = 24.0 \text{ parts} \][/tex]
### (b) Atomic Weight of Metal
The atomic weight can be determined based on the weight ratio between the metal and oxygen, and the known atomic weight of oxygen (16 parts).
Using the proportionality formula:
[tex]\[ \text{Atomic weight of the metal} = \frac{\text{Weight of the metal} \times \text{Atomic weight of oxygen}}{\text{Weight of oxygen}} \][/tex]
[tex]\[ \text{Atomic weight of the metal} = \frac{48 \text{ parts} \times 16}{32 \text{ parts}} = 24.0 \text{ parts} \][/tex]
### (c) Valency of Metal
The valency of the metal is provided in the problem statement as 2. Therefore:
[tex]\[ \text{Valency of the metal} = 2 \][/tex]
### Summary:
(a) Equivalent weight of the metal = 24.0 parts
(b) Atomic weight of the metal = 24.0 parts
(c) Valency of the metal = 2
