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Suppose the mean height in inches of all 9th grade students at one high school is estimated. The population standard deviation is 3 inches. The heights of 7 randomly selected students are [tex]$71, 75, 75, 61, 69, 65, 60$[/tex].

[tex]\[
\bar{x} = \text{Ex: } 12.34 \text{?}
\][/tex]

[tex]\[
\begin{array}{l}
\text{Margin of error at } 99\% \text{ confidence level} = \text{Ex: } 1.23 \\
99\% \text{ confidence interval} = [\text{Ex: } 12.34, \text{Ex: } 12.34]
\end{array}
\][/tex]

[smaller value, larger value]


Sagot :

Sure! Let's walk through the process for solving this problem step-by-step.

### Step 1: Calculating the Sample Mean ([tex]\(\bar{x}\)[/tex])

The heights of the 7 randomly selected students are:
[tex]\[ 71, 75, 75, 61, 69, 65, 60 \][/tex]

To find the sample mean, we sum these values and divide by the number of students:

[tex]\[ \bar{x} = \frac{71 + 75 + 75 + 61 + 69 + 65 + 60}{7} \][/tex]

Adding these values together:

[tex]\[ 71 + 75 + 75 + 61 + 69 + 65 + 60 = 476 \][/tex]

Now, dividing by the sample size ([tex]\(n = 7\)[/tex]):

[tex]\[ \bar{x} = \frac{476}{7} \approx 68.0 \][/tex]

### Step 2: Calculating the Margin of Error at 99% Confidence Level

Given:
- The population standard deviation ([tex]\(\sigma\)[/tex]) is 3 inches.
- The sample size ([tex]\(n\)[/tex]) is 7.
- The confidence level is 99%.

To find the margin of error, we need the standard error (SE) and the z-score corresponding to the 99% confidence level.

First, let's compute the standard error (SE):

[tex]\[ SE = \frac{\sigma}{\sqrt{n}} = \frac{3}{\sqrt{7}} \][/tex]

Next, we use the z-score for a 99% confidence level, which is approximately 2.576 (this value comes from standard normal distribution tables).

The margin of error (ME) is:

[tex]\[ ME = z \cdot SE \approx 2.576 \cdot \frac{3}{\sqrt{7}} \approx 2.92 \][/tex]

### Step 3: Calculating the 99% Confidence Interval

The confidence interval is calculated by adding and subtracting the margin of error from the sample mean.

The lower bound of the confidence interval is:

[tex]\[ \text{Lower bound} = \bar{x} - ME \approx 68.0 - 2.92 \approx 65.08 \][/tex]

The upper bound of the confidence interval is:

[tex]\[ \text{Upper bound} = \bar{x} + ME \approx 68.0 + 2.92 \approx 70.92 \][/tex]

### Final Results

- Sample Mean ([tex]\(\bar{x}\)[/tex]): [tex]\(68.0\)[/tex]
- Margin of error at 99% confidence level: [tex]\(2.92\)[/tex]
- 99% confidence interval: [tex]\([65.08, 70.92]\)[/tex]

So, based on the sample data, we estimate that the mean height of all 9th grade students at the high school is 68.0 inches, with a margin of error of 2.92 inches at the 99% confidence level. This gives us a 99% confidence interval of [65.08, 70.92] inches.