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Sagot :
Let's analyze the recorded outcomes and determine the frequency for each number of heads (0, 1, 2, and 3).
Given results:
[tex]\[ 2, 1, 0, 2, 2, 0, 2, 2, 3, 2, 1, 2, 1, 2, 1, 1, 2, 1, 3, 1 \][/tex]
To fill in the frequency table, we will count how often each number of heads appears in the list of results:
1. Count the number of times 0 heads appear:
- In the list: 0 appears twice.
2. Count the number of times 1 head appears:
- In the list: 1 appears seven times.
3. Count the number of times 2 heads appear:
- In the list: 2 appears nine times.
4. Count the number of times 3 heads appear:
- In the list: 3 appears twice.
We summarize these counts in the frequency table.
[tex]\[ \begin{tabular}{|c|c|} \hline \text{Number of Heads} & \text{Frequency} \\ \hline 0 & 2 \\ \hline 1 & 7 \\ \hline 2 & 9 \\ \hline 3 & 2 \\ \hline \end{tabular} \][/tex]
Thus:
- [tex]\( a = 2 \)[/tex]
- [tex]\( b = 7 \)[/tex]
- [tex]\( c = 9 \)[/tex]
- [tex]\( d = 2 \)[/tex]
This completes the frequency table with the calculated values.
Given results:
[tex]\[ 2, 1, 0, 2, 2, 0, 2, 2, 3, 2, 1, 2, 1, 2, 1, 1, 2, 1, 3, 1 \][/tex]
To fill in the frequency table, we will count how often each number of heads appears in the list of results:
1. Count the number of times 0 heads appear:
- In the list: 0 appears twice.
2. Count the number of times 1 head appears:
- In the list: 1 appears seven times.
3. Count the number of times 2 heads appear:
- In the list: 2 appears nine times.
4. Count the number of times 3 heads appear:
- In the list: 3 appears twice.
We summarize these counts in the frequency table.
[tex]\[ \begin{tabular}{|c|c|} \hline \text{Number of Heads} & \text{Frequency} \\ \hline 0 & 2 \\ \hline 1 & 7 \\ \hline 2 & 9 \\ \hline 3 & 2 \\ \hline \end{tabular} \][/tex]
Thus:
- [tex]\( a = 2 \)[/tex]
- [tex]\( b = 7 \)[/tex]
- [tex]\( c = 9 \)[/tex]
- [tex]\( d = 2 \)[/tex]
This completes the frequency table with the calculated values.
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