IDNLearn.com is the perfect place to get answers, share knowledge, and learn new things. Get the information you need quickly and accurately with our reliable and thorough Q&A platform.
Sagot :
Certainly! Let's balance the chemical equation step-by-step:
[tex]\[ P_4(s) + NaOH(aq) + H_2O(l) \rightarrow PH_3(g) + Na_2HPO_3(aq) \][/tex]
### Step 1: Balance the Phosphorus (P) atoms
In [tex]\(P_4\)[/tex], there are 4 phosphorus atoms on the left side. To balance the phosphorus atoms on both sides, we need 4 molecules of [tex]\(PH_3\)[/tex], each containing 1 phosphorus atom:
[tex]\[ P_4(s) \rightarrow 4PH_3(g) \][/tex]
### Step 2: Balance the Sodium (Na) atoms
Next, we need to balance the sodium atoms. We see that [tex]\(Na_2HPO_3\)[/tex] has 2 sodium atoms per molecule. Since we need to produce 4 molecules of [tex]\(Na_2HPO_3\)[/tex] to balance the phosphorus, we will need:
[tex]\[ 4 \times 2 = 8 \][/tex]
So, we need 8 molecules of [tex]\(NaOH\)[/tex]:
[tex]\[ NaOH(aq) \rightarrow 4Na_2HPO_3(aq) \][/tex]
### Step 3: Balance the Hydrogen (H) atoms
We now need to balance the hydrogen atoms. On the product side, we have [tex]\(4PH_3\)[/tex], each containing 3 hydrogen atoms:
[tex]\[ 4 \times 3 = 12 \text{ hydrogen atoms} \][/tex]
Adding to that, we have 8 hydrogen atoms from [tex]\(8NaOH\)[/tex]:
[tex]\[ 12 + 8 = 20 \text{ hydrogen atoms required} \][/tex]
Since each water molecule ([tex]\(H_2O\)[/tex]) contains 2 hydrogen atoms, we need:
[tex]\[ \frac{20}{2} = 10 \][/tex]
### Step 4: Balance the Oxygen (O) atoms
Finally, we balance the oxygen atoms. We have 10 molecules of [tex]\(H_2O\)[/tex], each containing one oxygen atom:
[tex]\[ 10 \text{ oxygen atoms from } H_2O \][/tex]
And 8 molecules of [tex]\(NaOH\)[/tex], each containing one oxygen atom:
[tex]\[ 8 \text{ oxygen atoms from } NaOH \][/tex]
Therefore:
[tex]\[ 10 + 8 = 18 \text{ oxygen atoms on the reactant side} \][/tex]
On the product side, each [tex]\(Na_2HPO_3\)[/tex] has 3 oxygen atoms and we have 4 of them:
[tex]\[ 4 \times 3 = 12 \text{ oxygen atoms} \][/tex]
We need to distribute the rest between [tex]\(H_2O\)[/tex] molecules and fit with hydrogen atoms:
[tex]\[ 18 \text{ atoms result to 6 water molecules to fit both oxygen and hydrogen atoms required on both sides of the equation} \][/tex]
### Final Balanced Equation
Combining all these steps, the balanced equation is:
[tex]\[ P_4(s) + 8NaOH(aq) + 6H_2O(l) \rightarrow 4PH_3(g) + 4Na_2HPO_3(aq) \][/tex]
This balanced equation ensures that the number of each type of atom is the same on both sides of the equation.
[tex]\[ P_4(s) + NaOH(aq) + H_2O(l) \rightarrow PH_3(g) + Na_2HPO_3(aq) \][/tex]
### Step 1: Balance the Phosphorus (P) atoms
In [tex]\(P_4\)[/tex], there are 4 phosphorus atoms on the left side. To balance the phosphorus atoms on both sides, we need 4 molecules of [tex]\(PH_3\)[/tex], each containing 1 phosphorus atom:
[tex]\[ P_4(s) \rightarrow 4PH_3(g) \][/tex]
### Step 2: Balance the Sodium (Na) atoms
Next, we need to balance the sodium atoms. We see that [tex]\(Na_2HPO_3\)[/tex] has 2 sodium atoms per molecule. Since we need to produce 4 molecules of [tex]\(Na_2HPO_3\)[/tex] to balance the phosphorus, we will need:
[tex]\[ 4 \times 2 = 8 \][/tex]
So, we need 8 molecules of [tex]\(NaOH\)[/tex]:
[tex]\[ NaOH(aq) \rightarrow 4Na_2HPO_3(aq) \][/tex]
### Step 3: Balance the Hydrogen (H) atoms
We now need to balance the hydrogen atoms. On the product side, we have [tex]\(4PH_3\)[/tex], each containing 3 hydrogen atoms:
[tex]\[ 4 \times 3 = 12 \text{ hydrogen atoms} \][/tex]
Adding to that, we have 8 hydrogen atoms from [tex]\(8NaOH\)[/tex]:
[tex]\[ 12 + 8 = 20 \text{ hydrogen atoms required} \][/tex]
Since each water molecule ([tex]\(H_2O\)[/tex]) contains 2 hydrogen atoms, we need:
[tex]\[ \frac{20}{2} = 10 \][/tex]
### Step 4: Balance the Oxygen (O) atoms
Finally, we balance the oxygen atoms. We have 10 molecules of [tex]\(H_2O\)[/tex], each containing one oxygen atom:
[tex]\[ 10 \text{ oxygen atoms from } H_2O \][/tex]
And 8 molecules of [tex]\(NaOH\)[/tex], each containing one oxygen atom:
[tex]\[ 8 \text{ oxygen atoms from } NaOH \][/tex]
Therefore:
[tex]\[ 10 + 8 = 18 \text{ oxygen atoms on the reactant side} \][/tex]
On the product side, each [tex]\(Na_2HPO_3\)[/tex] has 3 oxygen atoms and we have 4 of them:
[tex]\[ 4 \times 3 = 12 \text{ oxygen atoms} \][/tex]
We need to distribute the rest between [tex]\(H_2O\)[/tex] molecules and fit with hydrogen atoms:
[tex]\[ 18 \text{ atoms result to 6 water molecules to fit both oxygen and hydrogen atoms required on both sides of the equation} \][/tex]
### Final Balanced Equation
Combining all these steps, the balanced equation is:
[tex]\[ P_4(s) + 8NaOH(aq) + 6H_2O(l) \rightarrow 4PH_3(g) + 4Na_2HPO_3(aq) \][/tex]
This balanced equation ensures that the number of each type of atom is the same on both sides of the equation.
We appreciate your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. IDNLearn.com is committed to your satisfaction. Thank you for visiting, and see you next time for more helpful answers.
