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The circumference of an ellipse is approximated by [tex]C=2 \pi \sqrt{\frac{a^2+b^2}{2}}[/tex], where [tex]2a[/tex] and [tex]2b[/tex] are the lengths of the axes of the ellipse. Which equation is the result of solving the formula for the circumference for [tex]b[/tex]?

[tex]\[
\begin{array}{ll}
b=\sqrt{\frac{C^2}{\pi^2}-a^2} & b=\frac{C}{\sqrt{\pi}}-a \\
b=\frac{C}{\sqrt{2\pi}}-a & b=\sqrt{\frac{C^2}{2\pi^2}-a^2}
\end{array}
\][/tex]


Sagot :

To solve the given formula of the circumference of an ellipse for [tex]\( b \)[/tex], follow these detailed steps:

1. Begin with the given circumference formula:
[tex]\[ C = 2 \pi \sqrt{\frac{a^2 + b^2}{2}} \][/tex]

2. Isolate the square root expression by dividing both sides of the equation by [tex]\( 2 \pi \)[/tex]:
[tex]\[ \frac{C}{2 \pi} = \sqrt{\frac{a^2 + b^2}{2}} \][/tex]

3. Square both sides to remove the square root:
[tex]\[ \left(\frac{C}{2 \pi}\right)^2 = \frac{a^2 + b^2}{2} \][/tex]

4. Simplify the left side:
[tex]\[ \frac{C^2}{4 \pi^2} = \frac{a^2 + b^2}{2} \][/tex]

5. Multiply both sides by 2 to eliminate the fraction on the right:
[tex]\[ \frac{C^2}{2 \pi^2} = a^2 + b^2 \][/tex]

6. Isolate [tex]\( b^2 \)[/tex] by subtracting [tex]\( a^2 \)[/tex] from both sides:
[tex]\[ b^2 = \frac{C^2}{2 \pi^2} - a^2 \][/tex]

7. Finally, solve for [tex]\( b \)[/tex] by taking the square root of both sides:
[tex]\[ b = \sqrt{\frac{C^2}{2 \pi^2} - a^2} \][/tex]

The correct equation for [tex]\( b \)[/tex] is:
[tex]\[ b = \sqrt{\frac{C^2}{2 \pi^2} - a^2} \][/tex]

Therefore, the appropriate choice from the provided options is:
[tex]\[ b = \sqrt{\frac{C^2}{2 \pi^2} - a^2} \][/tex]