From beginner to expert, IDNLearn.com has answers for everyone. Get thorough and trustworthy answers to your queries from our extensive network of knowledgeable professionals.

Marina can bicycle 19.5 miles in the same time it takes her to run 6 miles. She bikes 9 miles per hour faster than she runs. At what speed does Marina run?

\begin{tabular}{|c|c|c|c|}
\hline & Distance (mi) & Rate (mph) & Time (hr) \\
\hline Bicycling & 19.5 & [tex]$r+9$[/tex] & [tex]$\frac{19.5}{r+9}$[/tex] \\
\hline Running & 6 & [tex]$r$[/tex] & [tex]$\frac{6}{r}$[/tex] \\
\hline \hline
\end{tabular}

A. 4 mph
B. 5 mph
C. 9 mph
D. 13 mph


Sagot :

To determine the speed at which Marina runs, let's break down the problem step-by-step.

First, we need to understand the relationships between distance, rate (speed), and time. The formula we use is:

[tex]\[ \text{Time} = \frac{\text{Distance}}{\text{Rate}} \][/tex]

Given the problem's details, let's define the variables and set up the corresponding equations:

1. Define the variables:
- Let [tex]\( r \)[/tex] be the speed at which Marina runs in miles per hour (mph).

2. Set up for bicycling:
- Distance: [tex]\( 19.5 \)[/tex] miles
- Rate: [tex]\( r + 9 \)[/tex] mph (since she bikes 9 mph faster than she runs)
- Time biking: [tex]\( \frac{19.5}{r + 9} \)[/tex]

3. Set up for running:
- Distance: [tex]\( 6 \)[/tex] miles
- Rate: [tex]\( r \)[/tex] mph
- Time running: [tex]\( \frac{6}{r} \)[/tex]

4. Determine the relationship between the two times:
The problem states that the time taken to bicycle 19.5 miles is the same as the time taken to run 6 miles. Therefore, we set the two time equations equal to each other:

[tex]\[ \frac{19.5}{r + 9} = \frac{6}{r} \][/tex]

5. Solve for [tex]\( r \)[/tex]:
Cross-multiply to eliminate the fractions:

[tex]\[ 19.5r = 6(r + 9) \][/tex]

Distribute [tex]\( 6 \)[/tex] on the right side:

[tex]\[ 19.5r = 6r + 54 \][/tex]

Move [tex]\( 6r \)[/tex] to the left side by subtracting [tex]\( 6r \)[/tex] from both sides:

[tex]\[ 19.5r - 6r = 54 \][/tex]

Simplify:

[tex]\[ 13.5r = 54 \][/tex]

Divide both sides by 13.5 to solve for [tex]\( r \)[/tex]:

[tex]\[ r = \frac{54}{13.5} \][/tex]

Simplify:

[tex]\[ r = 4 \][/tex]

So, the speed at which Marina runs is [tex]\( \boxed{4} \)[/tex] miles per hour.