IDNLearn.com offers a unique blend of expert answers and community insights. Ask anything and receive prompt, well-informed answers from our community of experienced experts.

Which expression is equivalent to [tex]$-2 \log _2 x + 4 \log _2 y + 4 \log _2 z$[/tex]?

A. [tex]\log _2 \left( \frac{x^2 y^4}{z^4} \right)[/tex]
B. [tex]\log _2 \left( \frac{y^4 z^4}{x^2} \right)[/tex]
C. [tex]\log _2 \left( \frac{y z^4}{x^2} \right)[/tex]
D. [tex]\log _2 \left( \frac{y z}{x} \right)^6[/tex]


Sagot :

To find the expression equivalent to [tex]\(-2 \log_2 x + 4 \log_2 y + 4 \log_2 z\)[/tex], we should use the properties of logarithms. Let's go through the problem step-by-step:

1. Logarithm Power Rule:
The power rule states that [tex]\( a \log_b c = \log_b(c^a) \)[/tex]. We apply this rule separately to each term in the given expression:

[tex]\[ -2 \log_2 x = \log_2(x^{-2}) \][/tex]
[tex]\[ 4 \log_2 y = \log_2(y^4) \][/tex]
[tex]\[ 4 \log_2 z = \log_2(z^4) \][/tex]

2. Combining Logarithms:
Now, we combine these logarithms using the logarithm addition and subtraction rules. The addition rule is [tex]\(\log_b(a) + \log_b(b) = \log_b(a \cdot b)\)[/tex] and the subtraction rule is [tex]\(\log_b(a) - \log_b(b) = \log_b\left(\frac{a}{b}\right)\)[/tex]. Combining the terms:

[tex]\[ \log_2(x^{-2}) + \log_2(y^4) + \log_2(z^4) \][/tex]

Combining all these logarithms into one, according to the rules:

[tex]\[ \log_2 \left( x^{-2} \cdot y^4 \cdot z^4 \right) \][/tex]

3. Simplify the Expression:
Simplify the inside of the logarithm:
[tex]\[ x^{-2} \cdot y^4 \cdot z^4 = \frac{y^4 \cdot z^4}{x^2} \][/tex]

Therefore:
[tex]\[ \log_2 \left( \frac{y^4 z^4}{x^2} \right) \][/tex]

So, the equivalent expression to [tex]\(-2 \log_2 x + 4 \log_2 y + 4 \log_2 z\)[/tex] is:
[tex]\[ \log_2 \left( \frac{y^4 z^4}{x^2} \right) \][/tex]

Thus, the correct option is:
[tex]\[ \boxed{\log_2\left(\frac{y^4 z^4}{x^2}\right)} \][/tex]
Thank you for using this platform to share and learn. Keep asking and answering. We appreciate every contribution you make. IDNLearn.com is committed to your satisfaction. Thank you for visiting, and see you next time for more helpful answers.