Explore a world of knowledge and get your questions answered on IDNLearn.com. Join our community to receive timely and reliable responses to your questions from knowledgeable professionals.
Sagot :
To determine the common ratio of the associated geometric sequence, follow these steps:
1. Understand the Sequence: The values given are [tex]\( y \)[/tex]-values of an exponential function corresponding to integer [tex]\( x \)[/tex]-values. The [tex]\( y \)[/tex]-values are [tex]\( 6, 36, 216, 1296, \)[/tex] and [tex]\( 7776 \)[/tex].
2. Identify the Formula: In a geometric sequence, each term after the first is found by multiplying the previous term by a constant common ratio, denoted as [tex]\( r \)[/tex].
3. Determine the Common Ratio: To find the common ratio [tex]\( r \)[/tex], divide any term by the preceding term in the sequence.
4. Calculate [tex]\( r \)[/tex]:
- Take the second term [tex]\( y_2 = 36 \)[/tex] and divide it by the first term [tex]\( y_1 = 6 \)[/tex]:
[tex]\[ r = \frac{y_2}{y_1} = \frac{36}{6} = 6 \][/tex]
So, the common ratio is [tex]\( 6 \)[/tex].
5. Verify Consistency: Ensure this ratio applies consistently throughout the sequence:
[tex]\[ r = \frac{y_3}{y_2} = \frac{216}{36} = 6 \][/tex]
[tex]\[ r = \frac{y_4}{y_3} = \frac{1296}{216} = 6 \][/tex]
[tex]\[ r = \frac{y_5}{y_4} = \frac{7776}{1296} = 6 \][/tex]
Since the common ratio [tex]\( r \)[/tex] is consistently [tex]\( 6 \)[/tex] throughout the sequence, the common ratio of the associated geometric sequence is [tex]\( 6 \)[/tex].
Thus, the answer is [tex]\( B. 6 \)[/tex].
1. Understand the Sequence: The values given are [tex]\( y \)[/tex]-values of an exponential function corresponding to integer [tex]\( x \)[/tex]-values. The [tex]\( y \)[/tex]-values are [tex]\( 6, 36, 216, 1296, \)[/tex] and [tex]\( 7776 \)[/tex].
2. Identify the Formula: In a geometric sequence, each term after the first is found by multiplying the previous term by a constant common ratio, denoted as [tex]\( r \)[/tex].
3. Determine the Common Ratio: To find the common ratio [tex]\( r \)[/tex], divide any term by the preceding term in the sequence.
4. Calculate [tex]\( r \)[/tex]:
- Take the second term [tex]\( y_2 = 36 \)[/tex] and divide it by the first term [tex]\( y_1 = 6 \)[/tex]:
[tex]\[ r = \frac{y_2}{y_1} = \frac{36}{6} = 6 \][/tex]
So, the common ratio is [tex]\( 6 \)[/tex].
5. Verify Consistency: Ensure this ratio applies consistently throughout the sequence:
[tex]\[ r = \frac{y_3}{y_2} = \frac{216}{36} = 6 \][/tex]
[tex]\[ r = \frac{y_4}{y_3} = \frac{1296}{216} = 6 \][/tex]
[tex]\[ r = \frac{y_5}{y_4} = \frac{7776}{1296} = 6 \][/tex]
Since the common ratio [tex]\( r \)[/tex] is consistently [tex]\( 6 \)[/tex] throughout the sequence, the common ratio of the associated geometric sequence is [tex]\( 6 \)[/tex].
Thus, the answer is [tex]\( B. 6 \)[/tex].
Thank you for being part of this discussion. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Thank you for visiting IDNLearn.com. We’re here to provide accurate and reliable answers, so visit us again soon.