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The values in the table represent an exponential function. What is the common ratio of the associated geometric sequence?

\begin{tabular}{|c|c|}
\hline [tex]$x$[/tex] & [tex]$y$[/tex] \\
\hline 1 & 6 \\
\hline 2 & 36 \\
\hline 3 & 216 \\
\hline 4 & 1296 \\
\hline 5 & 7776 \\
\hline
\end{tabular}

A. 5

B. 6

C. 36


Sagot :

To determine the common ratio of the associated geometric sequence, follow these steps:

1. Understand the Sequence: The values given are [tex]\( y \)[/tex]-values of an exponential function corresponding to integer [tex]\( x \)[/tex]-values. The [tex]\( y \)[/tex]-values are [tex]\( 6, 36, 216, 1296, \)[/tex] and [tex]\( 7776 \)[/tex].

2. Identify the Formula: In a geometric sequence, each term after the first is found by multiplying the previous term by a constant common ratio, denoted as [tex]\( r \)[/tex].

3. Determine the Common Ratio: To find the common ratio [tex]\( r \)[/tex], divide any term by the preceding term in the sequence.

4. Calculate [tex]\( r \)[/tex]:
- Take the second term [tex]\( y_2 = 36 \)[/tex] and divide it by the first term [tex]\( y_1 = 6 \)[/tex]:
[tex]\[ r = \frac{y_2}{y_1} = \frac{36}{6} = 6 \][/tex]
So, the common ratio is [tex]\( 6 \)[/tex].

5. Verify Consistency: Ensure this ratio applies consistently throughout the sequence:
[tex]\[ r = \frac{y_3}{y_2} = \frac{216}{36} = 6 \][/tex]
[tex]\[ r = \frac{y_4}{y_3} = \frac{1296}{216} = 6 \][/tex]
[tex]\[ r = \frac{y_5}{y_4} = \frac{7776}{1296} = 6 \][/tex]

Since the common ratio [tex]\( r \)[/tex] is consistently [tex]\( 6 \)[/tex] throughout the sequence, the common ratio of the associated geometric sequence is [tex]\( 6 \)[/tex].

Thus, the answer is [tex]\( B. 6 \)[/tex].