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Sagot :
To find an equivalent equation in the form [tex]\((x - h)^2 = k\)[/tex] for the given equation [tex]\(x^2 - 6x = 8\)[/tex], we will complete the square.
Here are the steps involved:
1. Start with the given equation:
[tex]\[ x^2 - 6x = 8 \][/tex]
2. Move the constant to the other side:
[tex]\[ x^2 - 6x - 8 = 0 \][/tex]
3. To complete the square: Focus on the terms involving [tex]\(x\)[/tex]. Take the coefficient of [tex]\(x\)[/tex], which is -6, and halve it, then square it:
[tex]\[ \left( \frac{-6}{2} \right)^2 = 9 \][/tex]
4. Add and subtract this square within the equation:
[tex]\[ x^2 - 6x + 9 = 8 + 9 \][/tex]
5. Simplify both sides:
[tex]\[ (x - 3)^2 = 17 \][/tex]
This results in the completed square form.
6. So, the equation equivalent to the given [tex]\(x^2 - 6x = 8\)[/tex] is:
[tex]\[ (x - 3)^2 = 17 \][/tex]
Therefore, the correct answer is:
[tex]\[ \boxed{(x-3)^2=17} \][/tex]
Selecting from the options provided, the correct choice is:
[tex]\[ \boxed{\text{B}} \][/tex]
Here are the steps involved:
1. Start with the given equation:
[tex]\[ x^2 - 6x = 8 \][/tex]
2. Move the constant to the other side:
[tex]\[ x^2 - 6x - 8 = 0 \][/tex]
3. To complete the square: Focus on the terms involving [tex]\(x\)[/tex]. Take the coefficient of [tex]\(x\)[/tex], which is -6, and halve it, then square it:
[tex]\[ \left( \frac{-6}{2} \right)^2 = 9 \][/tex]
4. Add and subtract this square within the equation:
[tex]\[ x^2 - 6x + 9 = 8 + 9 \][/tex]
5. Simplify both sides:
[tex]\[ (x - 3)^2 = 17 \][/tex]
This results in the completed square form.
6. So, the equation equivalent to the given [tex]\(x^2 - 6x = 8\)[/tex] is:
[tex]\[ (x - 3)^2 = 17 \][/tex]
Therefore, the correct answer is:
[tex]\[ \boxed{(x-3)^2=17} \][/tex]
Selecting from the options provided, the correct choice is:
[tex]\[ \boxed{\text{B}} \][/tex]
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