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Sagot :
Sure, let's break down the problem step-by-step:
1. Identify the fastest rowing speed: In our problem, we assume a reference value for the fastest rowing speed. Let's denote this speed as [tex]\( v \)[/tex].
2. Calculate 1.5 times the fastest rowing speed: We need to find [tex]\( 1.5 \times v \)[/tex].
3. Determine the result without doing any explicit calculation:
- If the fastest rowing speed is represented by [tex]\( v \)[/tex], 1.5 times this speed will consequently be [tex]\( 1.5 \times v \)[/tex].
- For example, if [tex]\( v \)[/tex] were 1 (just to illustrate):
[tex]\[ 1.5 \times 1 = 1.5 \][/tex]
- The result, 1.5 times the fastest rowing speed, will be 1.5.
4. Decimal places: The answer is [tex]\( 1.5 \)[/tex], which has one decimal place.
Thus, 1.5 times the fastest rowing speed is [tex]\( 1.5 \)[/tex] and the result has one decimal place.
1. Identify the fastest rowing speed: In our problem, we assume a reference value for the fastest rowing speed. Let's denote this speed as [tex]\( v \)[/tex].
2. Calculate 1.5 times the fastest rowing speed: We need to find [tex]\( 1.5 \times v \)[/tex].
3. Determine the result without doing any explicit calculation:
- If the fastest rowing speed is represented by [tex]\( v \)[/tex], 1.5 times this speed will consequently be [tex]\( 1.5 \times v \)[/tex].
- For example, if [tex]\( v \)[/tex] were 1 (just to illustrate):
[tex]\[ 1.5 \times 1 = 1.5 \][/tex]
- The result, 1.5 times the fastest rowing speed, will be 1.5.
4. Decimal places: The answer is [tex]\( 1.5 \)[/tex], which has one decimal place.
Thus, 1.5 times the fastest rowing speed is [tex]\( 1.5 \)[/tex] and the result has one decimal place.
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