IDNLearn.com is your go-to resource for finding answers to any question you have. Find reliable solutions to your questions quickly and accurately with help from our dedicated community of experts.

Identify the structure. Without evaluating, explain why [tex]$(-8.4)^5$[/tex] is less than [tex]$2^2$[/tex].

Sagot :

To compare [tex]\((-8.4)^5\)[/tex] and [tex]\(2^2\)[/tex] without evaluating their exact values, consider the following points:

1. Magnitude of the Base Numbers:
- The absolute value of [tex]\(-8.4\)[/tex] is [tex]\(8.4\)[/tex], which is significantly larger than the base [tex]\(2\)[/tex].
- In an exponentiation operation, the larger the base number, the larger the result, assuming positive exponents.

2. Sign of the Result for Negative Base:
- [tex]\(-8.4\)[/tex] is a negative number. When raised to an odd power (like [tex]\(5\)[/tex]), the result remains negative.
- [tex]\(2^2\)[/tex] is a positive number since any positive number raised to any power will remain positive.

3. General Behavior of Exponents:
- For positive exponents, the magnitude (absolute value) of [tex]\((-8.4)^5\)[/tex] will be [tex]\(8.4\)[/tex] raised to the power of [tex]\(5\)[/tex], which is a very large number.
- [tex]\(2^2\)[/tex] evaluates to [tex]\(4\)[/tex], which is a much smaller number compared to the magnitude of [tex]\(8.4^5\)[/tex].

Conclusion:
Given that [tex]\((-8.4)^5\)[/tex] is negative and a large number while [tex]\(2^2\)[/tex] is a small positive number, it is clear that [tex]\((-8.4)^5\)[/tex] is less than [tex]\(2^2\)[/tex]. This is because any negative number (no matter its magnitude) will always be less than a positive number.