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Hi!! please help by explaining how to solve this and if possible solve a for an example im a bit confused, please and thank you!

Hi Please Help By Explaining How To Solve This And If Possible Solve A For An Example Im A Bit Confused Please And Thank You class=

Sagot :

Answer:

See the below works.

Step-by-step explanation:

To solve this Diamond Problems, we refer to the top right diamond, which gives us the formulas for each small diamond. For each part of the big diamond:

  • left diamond stands for x
  • right diamond stands for y
  • top diamond stands for xy
  • bottom diamond stands for x+y

Diamond question b.

Given:

  • [tex]\texttt{left diamond}=\frac{3}{2}\ \Longrightarrow\ \bf x=\frac{3}{2}[/tex]
  • [tex]\texttt{right diamond}=\frac{3}{2}\ \Longrightarrow\ \bf y=\frac{3}{2}[/tex]

Then:

[tex]\begin{aligned}\texttt{top diamond}&=xy\\&=\frac{3}{2} \times\frac{3}{2} \\ &=\bf\frac{9}{4} \end{aligned}[/tex]

[tex]\begin{aligned}\texttt{bottom diamond}&=x+y\\&=\frac{3}{2} +\frac{3}{2} \\ &=\bf3 \end{aligned}[/tex]

Diamond question c.

Given:

  • [tex]\texttt{top diamond}=\frac{5}{4}\ \Longrightarrow\ \bf xy=\frac{5}{4}[/tex]
  • [tex]\texttt{right diamond}=-\frac{5}{2}\ \Longrightarrow\ \bf y=-\frac{5}{2}[/tex]

Then:

[tex]\begin{aligned}\texttt{left diamond}&=x\\&=xy\div y\\&=\frac{5}{4} \div\left(-\frac{5}{2} \right)\\&=\frac{5}{4} \times\left(-\frac{2}{5} \right)\\ &=-\bf\frac{1}{2} \end{aligned}[/tex]

[tex]\begin{aligned}\texttt{bottom diamond}&=x+y\\&=-\frac{1}{2} +\left(-\frac{5}{2}\right) \\ &=-\frac{1}{2}-\frac{5}{2}\\&=\bf-3 \end{aligned}[/tex]

Diamond question d.

Given:

  • [tex]\texttt{left diamond}=-10\ \Longrightarrow\ \bf x=-10[/tex]
  • [tex]\texttt{bottom diamond}=0\ \Longrightarrow\ \bf x+y=0[/tex]

Then:

[tex]\begin{aligned}\texttt{right diamond}&=y\\&=(x+y)-x\\&=0-(-10)\\&=0+10\\ &=\bf10\end{aligned}[/tex]

[tex]\begin{aligned}\texttt{top diamond}&=xy\\&=-10\times10\\&=\bf-100 \end{aligned}[/tex]

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