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Two points located on [tex]\stackrel{\rightharpoonup}{ JK }[/tex] are [tex]J(1,-4)[/tex] and [tex]K(-2,8)[/tex]. What is the slope of [tex]\overleftrightarrow{ JK }[/tex]?

A. -4
B. -2
C. [tex]-\frac{1}{4}[/tex]
D. [tex]\frac{1}{4}[/tex]
E. 4


Sagot :

To determine the slope of the line passing through the points [tex]\( J(1, -4) \)[/tex] and [tex]\( K(-2, 8) \)[/tex], we use the slope formula:

[tex]\[ m = \frac{y_2 - y_1}{x_2 - x_1} \][/tex]

Here, [tex]\((x_1, y_1)\)[/tex] are the coordinates of point [tex]\( J \)[/tex] and [tex]\((x_2, y_2)\)[/tex] are the coordinates of point [tex]\( K \)[/tex].

Given:
[tex]\( (x_1, y_1) = (1, -4) \)[/tex]
[tex]\( (x_2, y_2) = (-2, 8) \)[/tex]

Now, substitute these values into the formula:

[tex]\[ m = \frac{8 - (-4)}{-2 - 1} \][/tex]

Simplify the numerator and the denominator:

[tex]\[ m = \frac{8 + 4}{-2 - 1} \][/tex]
[tex]\[ m = \frac{12}{-3} \][/tex]

Perform the division:

[tex]\[ m = -4 \][/tex]

Thus, the slope of the line [tex]\( \overleftrightarrow{ JK } \)[/tex] is [tex]\(-4\)[/tex].

The correct answer is:
A. [tex]\(-4\)[/tex]
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