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Solve the equation:
[tex]\[ 3x + 2 = 17 \][/tex]
A. [tex]\( x = 5 \)[/tex] B. [tex]\( x = 12 \)[/tex] C. [tex]\( x = 3 \)[/tex] D. [tex]\( x = \frac{19}{3} \)[/tex]
The given equation is: [tex]\[ 3x + 2 = 17 \][/tex]
1. Subtract 2 from both sides to isolate the term containing [tex]\( x \)[/tex]: [tex]\[
3x + 2 - 2 = 17 - 2
\][/tex] This simplifies to: [tex]\[
3x = 15
\][/tex]
2. Divide both sides by 3 to solve for [tex]\( x \)[/tex]: [tex]\[
x = \frac{15}{3}
\][/tex] This simplifies to: [tex]\[
x = 5
\][/tex]
Therefore, the solution to the equation [tex]\( 3x + 2 = 17 \)[/tex] is [tex]\( x = 5 \)[/tex].
In order to solve this equation we first need to simplify it into the y=mx+b formula, however, from early on we can see that there is no “y”, but we will still use the same process.
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