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Sagot :
Let's solve the problem step-by-step to determine the difference in total account balances between simple interest and monthly compounded interest.
1. Given Values:
- Principal Amount ([tex]\( P \)[/tex]): \[tex]$5900 - Annual Percentage Rate (APR): 2.996% = 0.02996 (as a decimal) - Time (\( T \)): 15 years 2. Simple Interest Calculation: The formula for simple interest is: \[ \text{Simple Interest} = P \times r \times T \] Where: - \( P \) is the principal amount - \( r \) is the annual interest rate (as a decimal) - \( T \) is the time in years \[ \text{Simple Interest} = 5900 \times 0.02996 \times 15 \] \[ \text{Simple Interest} = 2651.46 \] The total amount with simple interest is: \[ \text{Total (Simple)} = P + \text{Simple Interest} \] \[ \text{Total (Simple)} = 5900 + 2651.46 \] \[ \text{Total (Simple)} = 8551.46 \] 3. Compound Interest Calculation: The formula for compound interest with monthly compounding is: \[ A = P \left(1 + \frac{r}{n}\right)^{nt} \] Where: - \( A \) is the amount of money accumulated after n years, including interest. - \( P \) is the principal amount. - \( r \) is the annual interest rate (decimal). - \( n \) is the number of times interest is compounded per year. - \( t \) is the number of years the money is invested. For monthly compounding: - \( n \) = 12 (since interest is compounded monthly) - \( t \) = 15 years \[ A = 5900 \left(1 + \frac{0.02996}{12}\right)^{12 \times 15} \] \[ A = 5900 \left(1 + 0.0024967 \right)^{180} \] \[ A = 5900 \times 1.056.472... \] \[ A \approx 9242.31 \] 4. Difference between Compound and Simple Interest Totals: \[ \text{Difference} = \text{Total (Compound)} - \text{Total (Simple)} \] \[ \text{Difference} = 9242.31 - 8551.46 \] \[ \text{Difference} = 690.85 \] So, the difference in the total account balances if simple interest is applied, compared to monthly compounded interest is approximately: \[ \boxed{690.85} \] Therefore, the correct answer is not one of the options given in the question. The closest accurate numerical result to the true difference is $[/tex]\[tex]$ 690.85$[/tex].
1. Given Values:
- Principal Amount ([tex]\( P \)[/tex]): \[tex]$5900 - Annual Percentage Rate (APR): 2.996% = 0.02996 (as a decimal) - Time (\( T \)): 15 years 2. Simple Interest Calculation: The formula for simple interest is: \[ \text{Simple Interest} = P \times r \times T \] Where: - \( P \) is the principal amount - \( r \) is the annual interest rate (as a decimal) - \( T \) is the time in years \[ \text{Simple Interest} = 5900 \times 0.02996 \times 15 \] \[ \text{Simple Interest} = 2651.46 \] The total amount with simple interest is: \[ \text{Total (Simple)} = P + \text{Simple Interest} \] \[ \text{Total (Simple)} = 5900 + 2651.46 \] \[ \text{Total (Simple)} = 8551.46 \] 3. Compound Interest Calculation: The formula for compound interest with monthly compounding is: \[ A = P \left(1 + \frac{r}{n}\right)^{nt} \] Where: - \( A \) is the amount of money accumulated after n years, including interest. - \( P \) is the principal amount. - \( r \) is the annual interest rate (decimal). - \( n \) is the number of times interest is compounded per year. - \( t \) is the number of years the money is invested. For monthly compounding: - \( n \) = 12 (since interest is compounded monthly) - \( t \) = 15 years \[ A = 5900 \left(1 + \frac{0.02996}{12}\right)^{12 \times 15} \] \[ A = 5900 \left(1 + 0.0024967 \right)^{180} \] \[ A = 5900 \times 1.056.472... \] \[ A \approx 9242.31 \] 4. Difference between Compound and Simple Interest Totals: \[ \text{Difference} = \text{Total (Compound)} - \text{Total (Simple)} \] \[ \text{Difference} = 9242.31 - 8551.46 \] \[ \text{Difference} = 690.85 \] So, the difference in the total account balances if simple interest is applied, compared to monthly compounded interest is approximately: \[ \boxed{690.85} \] Therefore, the correct answer is not one of the options given in the question. The closest accurate numerical result to the true difference is $[/tex]\[tex]$ 690.85$[/tex].
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