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Determine the number of possible imaginary (complex) solutions. Separate multiple answers by commas.

a) [tex] x^3 - x^2 - 36x + 36 [/tex]


Sagot :

To solve the polynomial equation [tex]\(x^3 - x^2 - 36x + 36 = 0\)[/tex] and determine the number of possible imaginary (complex) solutions, follow these steps:

1. Set up the equation: We start by examining the polynomial given:
[tex]\[ x^3 - x^2 - 36x + 36 = 0 \][/tex]

2. Find the roots of the polynomial: Through solving this cubic equation, we obtain the roots of the equation. For this specific polynomial, the roots are found to be:
[tex]\[ x = -6, \quad x = 1, \quad x = 6 \][/tex]

3. Classify the roots: Next, we need to determine the nature of these roots. A complex (imaginary) root in this context means a root that has a non-zero imaginary component. When examining the roots provided:
[tex]\[ -6, \quad 1, \quad 6 \][/tex]
we notice that all these numbers are real numbers.

4. Determine the number of imaginary solutions: Since none of the roots have an imaginary component, we conclude that the number of imaginary (complex) solutions is:
[tex]\[ 0 \][/tex]

Thus, the polynomial equation [tex]\(x^3 - x^2 - 36x + 36 = 0\)[/tex] has 0 imaginary (complex) solutions. The correct answer is:
```
(0)
```