Sure, let's break down the problem and find the dimensions of the room.
1. Given Information:
- The area of the room is [tex]\( 44 \, \text{m}^2 \)[/tex].
- The length of the room is [tex]\( 70 \, \text{m} \)[/tex].
2. Identify the relationship:
- We know that the area of a rectangle (or room) is calculated by multiplying the length by the width.
- Let [tex]\( w \)[/tex] represent the width of the room.
- Therefore, the formula for the area would be:
[tex]\[
\text{Area} = \text{Length} \times \text{Width}
\][/tex]
- Substituting the known values into the formula, we get:
[tex]\[
44 = 70 \times w
\][/tex]
3. Solve for [tex]\( w \)[/tex]:
- To find the width [tex]\( w \)[/tex], we need to rearrange the formula to solve for [tex]\( w \)[/tex]:
[tex]\[
w = \frac{44}{70}
\][/tex]
- When we divide [tex]\( 44 \)[/tex] by [tex]\( 70 \)[/tex], we get:
[tex]\[
w = 0.6285714285714286 \, \text{m}
\][/tex]
4. State the dimensions:
- The width of the room is approximately [tex]\( 0.63 \, \text{m} \)[/tex] (rounded to two decimal places for simplicity).
- The length of the room remains [tex]\( 70 \, \text{m} \)[/tex].
5. Conclusion:
- The dimensions of the room are:
- Width: [tex]\( 0.63 \, \text{m} \)[/tex]
- Length: [tex]\( 70 \, \text{m} \)[/tex]
So, the dimensions of the room are a width of approximately [tex]\( 0.63 \, \text{m} \)[/tex] and a length of [tex]\( 70 \, \text{m} \)[/tex].
