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Find the average \[m\] of \[z_1=(-10-2i)\] and \[z_2=(8+2i)\]. Express your answer in rectangular form.

Sagot :

Sqdancefanidn

Answer:

  -1

Step-by-step explanation:

You want the mean of (-10-2i) and (8+2i).

Average

The mean (average) of two numbers is half their sum:

  [tex]m=\dfrac{(-10-2i)+(8+2i)}{2}=\dfrac{-10+8}{2}+\dfrac{-2+2}{2}i\\\\\\m=-\dfrac{2}{2}+\dfrac{0}{2}i=\boxed{-1}[/tex]

The average of z₁ and z₂ is -1.

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Additional comment

If you need the imaginary part shown, you could write it as m = -1 +0i.

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