Connect with knowledgeable experts and enthusiasts on IDNLearn.com. Get the information you need quickly and accurately with our reliable and thorough Q&A platform.
Sagot :
Let's determine the number of possible imaginary (complex) solutions for each given polynomial.
### Part (a): [tex]\( x^4 - 7x^3 - x^2 + 67x - 60 = 0 \)[/tex]
To find the roots of the polynomial [tex]\( x^4 - 7x^3 - x^2 + 67x - 60 \)[/tex], apply the Fundamental Theorem of Algebra, which states that a polynomial of degree [tex]\( n \)[/tex] has exactly [tex]\( n \)[/tex] roots, considering their multiplicity and including complex roots.
1. The polynomial is of degree 4, so there will be 4 roots in total.
2. Polynomials with real coefficients have roots that appear in conjugate pairs if they are complex.
To determine the number of complex (imaginary) roots:
- Check if the polynomial can be factored easily. For polynomials with real coefficients, if a complex number is a root, then its conjugate is also a root.
From the provided information, we know:
- There are 0 imaginary (complex) roots.
### Part (b): [tex]\( -4x + 4 = 0 \)[/tex]
For the linear equation [tex]\( -4x + 4 = 0 \)[/tex]:
1. This is a linear polynomial of degree 1.
2. A linear polynomial has exactly one root.
3. Since the coefficient of [tex]\( x \)[/tex] and the constant term are real numbers, there cannot be any complex roots.
From the provided information, we know:
- There are 0 imaginary (complex) roots.
### Part (c): [tex]\( x^2 + 2x - 3 = 0 \)[/tex]
To solve the quadratic equation [tex]\( x^2 + 2x - 3 = 0 \)[/tex]:
1. This is a quadratic polynomial of degree 2, so it can have up to 2 roots.
2. Use the quadratic formula to determine the roots: [tex]\( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \)[/tex].
Here, [tex]\( a = 1 \)[/tex], [tex]\( b = 2 \)[/tex], and [tex]\( c = -3 \)[/tex].
The discriminant [tex]\( \Delta \)[/tex] is given by [tex]\( \Delta = b^2 - 4ac \)[/tex]. Plug in the values:
[tex]\[ \Delta = 2^2 - 4(1)(-3) = 4 + 12 = 16 \][/tex]
Since the discriminant is positive ([tex]\( \Delta = 16 \)[/tex]), the quadratic equation has two distinct real roots.
From the provided information, we know:
- There are 0 imaginary (complex) roots.
In summary:
- For [tex]\( x^4 - 7x^3 - x^2 + 67x - 60 = 0 \)[/tex]:
- Number of imaginary (complex) roots: 0
- For [tex]\( -4x + 4 = 0 \)[/tex]:
- Number of imaginary (complex) roots: 0
- For [tex]\( x^2 + 2x - 3 = 0 \)[/tex]:
- Number of imaginary (complex) roots: 0
### Part (a): [tex]\( x^4 - 7x^3 - x^2 + 67x - 60 = 0 \)[/tex]
To find the roots of the polynomial [tex]\( x^4 - 7x^3 - x^2 + 67x - 60 \)[/tex], apply the Fundamental Theorem of Algebra, which states that a polynomial of degree [tex]\( n \)[/tex] has exactly [tex]\( n \)[/tex] roots, considering their multiplicity and including complex roots.
1. The polynomial is of degree 4, so there will be 4 roots in total.
2. Polynomials with real coefficients have roots that appear in conjugate pairs if they are complex.
To determine the number of complex (imaginary) roots:
- Check if the polynomial can be factored easily. For polynomials with real coefficients, if a complex number is a root, then its conjugate is also a root.
From the provided information, we know:
- There are 0 imaginary (complex) roots.
### Part (b): [tex]\( -4x + 4 = 0 \)[/tex]
For the linear equation [tex]\( -4x + 4 = 0 \)[/tex]:
1. This is a linear polynomial of degree 1.
2. A linear polynomial has exactly one root.
3. Since the coefficient of [tex]\( x \)[/tex] and the constant term are real numbers, there cannot be any complex roots.
From the provided information, we know:
- There are 0 imaginary (complex) roots.
### Part (c): [tex]\( x^2 + 2x - 3 = 0 \)[/tex]
To solve the quadratic equation [tex]\( x^2 + 2x - 3 = 0 \)[/tex]:
1. This is a quadratic polynomial of degree 2, so it can have up to 2 roots.
2. Use the quadratic formula to determine the roots: [tex]\( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \)[/tex].
Here, [tex]\( a = 1 \)[/tex], [tex]\( b = 2 \)[/tex], and [tex]\( c = -3 \)[/tex].
The discriminant [tex]\( \Delta \)[/tex] is given by [tex]\( \Delta = b^2 - 4ac \)[/tex]. Plug in the values:
[tex]\[ \Delta = 2^2 - 4(1)(-3) = 4 + 12 = 16 \][/tex]
Since the discriminant is positive ([tex]\( \Delta = 16 \)[/tex]), the quadratic equation has two distinct real roots.
From the provided information, we know:
- There are 0 imaginary (complex) roots.
In summary:
- For [tex]\( x^4 - 7x^3 - x^2 + 67x - 60 = 0 \)[/tex]:
- Number of imaginary (complex) roots: 0
- For [tex]\( -4x + 4 = 0 \)[/tex]:
- Number of imaginary (complex) roots: 0
- For [tex]\( x^2 + 2x - 3 = 0 \)[/tex]:
- Number of imaginary (complex) roots: 0
We value your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. For trustworthy and accurate answers, visit IDNLearn.com. Thanks for stopping by, and see you next time for more solutions.