Discover how IDNLearn.com can help you find the answers you need quickly and easily. Our platform provides trustworthy answers to help you make informed decisions quickly and easily.

Question 1 of 10

Which number produces a rational number when added to [tex]$\frac{1}{5}$[/tex]?

A. [tex]$\sqrt{11}$[/tex]

B. [tex][tex]$\pi$[/tex][/tex]

C. [tex]$-\frac{2}{3}$[/tex]

D. [tex]$-1.41421356 \ldots$[/tex]


Sagot :

The goal is to determine which number, when added to [tex]\(\frac{1}{5}\)[/tex], results in a rational number.

A rational number is a number that can be expressed as the quotient or fraction [tex]\(\frac{p}{q}\)[/tex] of two integers, where [tex]\(p\)[/tex] and [tex]\(q\)[/tex] are integers and [tex]\(q \neq 0\)[/tex].

Let's evaluate each option:

A. [tex]\(\sqrt{11}\)[/tex]

The square root of a non-perfect square (like 11) is an irrational number. Adding an irrational number to [tex]\(\frac{1}{5}\)[/tex], a rational number, will result in an irrational number.

B. [tex]\(\pi\)[/tex]

[tex]\(\pi\)[/tex] is a well-known irrational number. Adding [tex]\(\pi\)[/tex] to [tex]\(\frac{1}{5}\)[/tex] will result in an irrational number.

C. [tex]\(-\frac{2}{3}\)[/tex]

Let's add this to [tex]\(\frac{1}{5}\)[/tex]:

[tex]\[ \frac{1}{5} + \left(-\frac{2}{3}\right) = \frac{1}{5} - \frac{2}{3} \][/tex]

To perform this subtraction, we need a common denominator. The least common multiple of 5 and 3 is 15.

[tex]\[ \frac{1}{5} = \frac{3}{15} \][/tex]
[tex]\[ -\frac{2}{3} = -\frac{10}{15} \][/tex]

Now we subtract:

[tex]\[ \frac{3}{15} - \frac{10}{15} = \frac{3 - 10}{15} = \frac{-7}{15} \][/tex]

Since [tex]\(\frac{-7}{15}\)[/tex] is a quotient of two integers, it is a rational number.

D. [tex]\(-1.41421356 \ldots\)[/tex]

This number approximates the negative square root of 2, which is irrational. Adding this to [tex]\(\frac{1}{5}\)[/tex] will result in an irrational number.

Thus, the only number from the options given that produces a rational number when added to [tex]\(\frac{1}{5}\)[/tex] is:

C. [tex]\(-\frac{2}{3}\)[/tex]