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Given that the cube root of 27 is 3, what is [tex]$27^{\frac{4}{3}}$[/tex]?

A. 12
B. 108
C. 81
D. 4


Sagot :

To find [tex]\(27^{\frac{4}{3}}\)[/tex], we can follow these steps:

1. First, recall that the exponent [tex]\(\frac{4}{3}\)[/tex] can be broken down into two parts: the cube root (i.e., raising to the power of [tex]\(\frac{1}{3}\)[/tex]) and then raising to the power of 4.

2. We know that [tex]\(27\)[/tex] can be expressed as [tex]\(3^3\)[/tex]. Therefore, we can write:
[tex]\[ 27 = 3^3 \][/tex]

3. Applying the exponent [tex]\(\frac{4}{3}\)[/tex] to [tex]\(27\)[/tex]:
[tex]\[ 27^{\frac{4}{3}} = (3^3)^{\frac{4}{3}} \][/tex]

4. Using the property of exponents [tex]\((a^m)^n = a^{m \cdot n}\)[/tex], we can simplify:
[tex]\[ (3^3)^{\frac{4}{3}} = 3^{3 \cdot \frac{4}{3}} = 3^4 \][/tex]

5. Calculate [tex]\(3^4\)[/tex]:
[tex]\[ 3^4 = 3 \times 3 \times 3 \times 3 = 81 \][/tex]

Hence, the value of [tex]\(27^{\frac{4}{3}}\)[/tex] is [tex]\(81\)[/tex].

The options given are:
- 12
- 108
- 81
- 4

The correct answer is:
[tex]\[ \boxed{81} \][/tex]

Answer:

81

Step-by-step explanation:

[tex]27^{\frac{4}{3} }[/tex] can also be written as [tex]\sqrt[3]{27^{4} }[/tex]

You can now solve for the answer using this rewritten equation *remember to use your calculator!*:

  1. [tex]\sqrt[3]{27^{4} }[/tex]
  2. [tex]\sqrt[3]{531441 }[/tex]
  3. =81

Your answer is 81

Hope this helped!