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Multiply.

[tex](3-4i)(-2-2i)[/tex]

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[tex]\square[/tex]


Sagot :

To multiply the complex numbers [tex]\( (3 - 4i) \)[/tex] and [tex]\( (-2 - 2i) \)[/tex], follow these steps:

1. Express the multiplication in distributed form:
[tex]\[ (3 - 4i)(-2 - 2i) = 3(-2 - 2i) + (-4i)(-2 - 2i) \][/tex]

2. Distribute each term in the parentheses:
- For [tex]\(3(-2 - 2i)\)[/tex]:
[tex]\[ 3(-2) + 3(-2i) = -6 - 6i \][/tex]

- For [tex]\((-4i)(-2 - 2i)\)[/tex]:
[tex]\[ (-4i)(-2) + (-4i)(-2i) = 8i + 8i^2 \][/tex]

3. Recall that [tex]\( i^2 = -1 \)[/tex]:
[tex]\[ 8i^2 = 8(-1) = -8 \][/tex]

4. Combine the results:
[tex]\[ -6 - 6i + 8i - 8 \][/tex]

5. Combine the real parts and the imaginary parts:
- Combine the real parts:
[tex]\[ -6 - 8 = -14 \][/tex]

- Combine the imaginary parts:
[tex]\[ -6i + 8i = 2i \][/tex]

Therefore, the product of the complex numbers [tex]\( (3 - 4i) \)[/tex] and [tex]\( (-2 - 2i) \)[/tex] is:
[tex]\[ \boxed{(-14 + 2i)} \][/tex]
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