Answered

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The rectangular Block measures 40cm
x25cmx 5cm and is made of a material
of density 7800kg/m^3. Calculate the
pressure the block exerts on the floor
when it stands on the smallest of its.
Surfaces
​

Sagot :

MathPhysidn

Answer:

3.12×10⁴ N/m²

Explanation:

Pressure (P) is equal to force (F) divided by area (A). In this case, the force is the weight of the block, which is equal to the mass (m) times the acceleration due to gravity (g). The mass of the block is equal to the density (ρ) times the volume (V). The volume of a rectangular prism is width times length times height (W×L×H).

The volume of the block is:

V = WLH

V = (0.05 m) (0.40 m) (0.25 m)

V = 0.005 m³

The mass of the block is:

m = ρV

m = (7800 kg/m³) (0.005 m³)

m = 39 kg

The weight of the block is:

F = mg

F = (39 kg) (10 m/s²)

F = 390 N

The pressure on the floor is:

P = F/A

P = (390 N) / (0.05 m × 0.25 m)

P = 31,200 N/m²

The pressure on the floor is 31,200 N/m², or 3.12×10⁴ N/m².

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