IDNLearn.com: Where your questions are met with thoughtful and precise answers. Discover prompt and accurate answers from our experts, ensuring you get the information you need quickly.

Given that [tex]$y$[/tex] varies directly with [tex]$x$[/tex] in the table below, what is the value of [tex]$y$[/tex] if the value of [tex]$x$[/tex] is 7?

\begin{tabular}{|c|c|c|c|c|}
\hline
[tex]$x$[/tex] & 2 & 4 & 6 & 10 \\
\hline
[tex]$y$[/tex] & 12 & 24 & 36 & 60 \\
\hline
\end{tabular}

A. 37
B. 42
C. 48
D. 54


Sagot :

To determine the value of [tex]\( y \)[/tex] when [tex]\( x = 7 \)[/tex] given that [tex]\( y \)[/tex] varies directly with [tex]\( x \)[/tex], follow the detailed steps below:

### Step 1: Identify the Relationship Between [tex]\( x \)[/tex] and [tex]\( y \)[/tex]

Since [tex]\( y \)[/tex] varies directly with [tex]\( x \)[/tex], the relationship can be written as [tex]\( y = kx \)[/tex], where [tex]\( k \)[/tex] is the constant of proportionality.

### Step 2: Determine the Constant of Proportionality

From the provided table:

[tex]\[ \begin{array}{|c|c|c|c|c|} \hline x & 2 & 4 & 6 & 10 \\ \hline y & 12 & 24 & 36 & 60 \\ \hline \end{array} \][/tex]

Choose any pair [tex]\((x, y)\)[/tex] from the table to calculate [tex]\( k \)[/tex]. Using the first pair:

[tex]\[ x = 2, \quad y = 12 \][/tex]

Substitute these values into the equation [tex]\( y = kx \)[/tex]:

[tex]\[ 12 = k \cdot 2 \][/tex]

Solve for [tex]\( k \)[/tex]:

[tex]\[ k = \frac{12}{2} = 6 \][/tex]

Thus, the constant of proportionality [tex]\( k \)[/tex] is 6.

### Step 3: Calculate [tex]\( y \)[/tex] When [tex]\( x = 7 \)[/tex]

Now, use the constant [tex]\( k \)[/tex] to find [tex]\( y \)[/tex] when [tex]\( x = 7 \)[/tex]:

[tex]\[ y = kx \][/tex]

Substitute [tex]\( k = 6 \)[/tex] and [tex]\( x = 7 \)[/tex]:

[tex]\[ y = 6 \cdot 7 = 42 \][/tex]

### Step 4: Verify the Answer with Given Choices

Given the possible choices: 37, 42, 48, and 54.

The value of [tex]\( y \)[/tex] when [tex]\( x = 7 \)[/tex] is [tex]\(\boxed{42}\)[/tex].
Thank you for joining our conversation. Don't hesitate to return anytime to find answers to your questions. Let's continue sharing knowledge and experiences! Thank you for visiting IDNLearn.com. We’re here to provide dependable answers, so visit us again soon.